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  "body": "\n## Statement\n\nLet $\\Pi$ be an [[absolute plane|VKFPCSRNDH]] that satisfies the axiom of Archimedes.\nThen the sum of the three [[angles|0GJAJC6TNZ]] of every [[triangle|0CTNFGYMM2]] in $\\Pi$ is at most two right angles.\n\n## Remarks\n\nThe proof starts from a triangle $ABC$ and builds a new triangle with the same angle sum, one of whose angles is at most half of the angle at $A$.\nRepeating this $n$ times gives a triangle with the same angle sum and an angle at most $2^{-n}$ times the angle at $A$.\nIf the angle sum exceeded two right angles by some angle $\\varepsilon$, the axiom of Archimedes would give a step where this small angle is less than $\\varepsilon$.\nThen the other two angles would sum to more than two right angles, which contradicts the [[exterior angle theorem|0NTSE7EREA]].\nThe axiom of Archimedes is needed: Max Dehn built non-Archimedean geometries in which the other axioms hold and some triangles have angle sum greater than two right angles.\n\n## Explanations\n\n### L1 human\n\nWithout the parallel postulate, one cannot prove that the angles of a triangle add up to $180^\\circ$.\nBut one can still prove that they never add up to more than $180^\\circ$.\nIn the Euclidean plane the sum is exactly $180^\\circ$, and in the hyperbolic plane it is always less.\n\n### L2 human\n\nThe theorem is one of the main results of absolute geometry.\nWith it, the parallel postulate is equivalent to the existence of a single triangle with angle sum $180^\\circ$.\nThe defect of a triangle is two right angles minus its angle sum.\nIt is additive when a triangle is cut into two, and in the hyperbolic plane it is proportional to the area.\n",
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    "name": "Saccheri–Legendre theorem",
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  "name": "Saccheri–Legendre theorem",
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