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  "body": "\n## Problem\n\nLet $a \u003c b$ and $A, B, \\ell \\in \\R$, and let $L, G \\colon [a, b] \\times \\R \\times \\R \\to \\R$, written $L(x, z, p)$ and $G(x, z, p)$, be of class $C^2$.\nSet $J(y) = \\int_a^b L(x, y, y') \\, dx$ and $K(y) = \\int_a^b G(x, y, y') \\, dx$, two [[integral functionals|JRQZ803Q5Y]].\nThe *isoperimetric problem* asks for a minimiser of $J$ among the [[admissible functions|G7T008BEWY]] $y \\in C^1([a, b])$ with $y(a) = A$, $y(b) = B$ and the integral constraint $K(y) = \\ell$.\n\n## Remarks\n\nThe name comes from the classical problem of the largest area enclosed by a curve of given length, the case where $K$ is arc length.\n[[Dido's problem|FABJSZ9D3S]] is a version of it.\n\nThe basic necessary condition is Euler's multiplier rule.\nLet $y_0 \\in C^2([a, b])$ be a minimiser, and suppose that $y_0$ does not solve the [[Euler–Lagrange equation|PS0VV149ET]] of $K$.\nThen there is $\\lambda \\in \\R$ such that $y_0$ solves the Euler–Lagrange equation of $L - \\lambda G$:\n$$\\frac{d}{dx} \\big( L_p - \\lambda G_p \\big) = L_z - \\lambda G_z \\quad \\text{on } [a, b].$$\nIt follows from [[Lagrange multipliers on Banach spaces|Q7QK3PF806]] with constraint space $\\R$.\nIf $y_0$ solves the Euler–Lagrange equation of $K$, the rule must be replaced by one with multipliers $(\\lambda_0, \\lambda) \\ne (0, 0)$ for $\\lambda_0 L - \\lambda G$, where $\\lambda_0 = 0$ is possible.\n\nThe [[catenary problem|8REBFQD6E0]] is an isoperimetric problem: it minimises potential energy at fixed length.\n\n## Explanations\n\n### L1 human\n\nMany problems ask for the best curve when some total amount is fixed: the length of a fence, the mass of a chain, the area under a graph.\nThe fixed amount is written as a second integral, and the problem is to minimise the first integral while the second keeps its value.\nAs for constrained problems in calculus, the answer is found by adding a multiple of the constraint to the functional, with an unknown multiplier.\n",
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