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  "body": "\n## Definition\n\nLet $\\R^n$ have the standard inner product $\\langle \\cdot, \\cdot \\rangle$.\nFor $\\alpha \\in \\R^n \\setminus \\set{0}$, let $\\sigma_\\alpha(x) = x - 2 \\frac{\\langle \\alpha, x \\rangle}{\\langle \\alpha, \\alpha \\rangle} \\alpha$ be the [[reflection|06BRDF3F0E]] in the hyperplane orthogonal to $\\alpha$.\nLet $R \\subset \\R^n \\setminus \\set{0}$ be a root system: a finite set such that $\\sigma_\\alpha(R) = R$ and $R \\cap \\R \\alpha = \\set{\\alpha, -\\alpha}$ for every $\\alpha \\in R$.\nLet $W$ be the finite [[reflection group|G6FND7X69J]] generated by the $\\sigma_\\alpha$, and let $R_+ \\subset R$ contain exactly one of $\\alpha, -\\alpha$ for each $\\alpha \\in R$.\nLet $k \\colon R \\to \\C$ be a multiplicity function, that is, $k(w \\alpha) = k(\\alpha)$ for all $w \\in W$ and $\\alpha \\in R$.\nFor $\\xi \\in \\R^n$, the *Dunkl operator* $T_\\xi$ acts on smooth functions $f$ on $\\R^n$ by\n$$T_\\xi f(x) = \\partial_\\xi f(x) + \\sum_{\\alpha \\in R_+} k(\\alpha)\\, \\langle \\alpha, \\xi \\rangle\\, \\frac{f(x) - f(\\sigma_\\alpha x)}{\\langle \\alpha, x \\rangle},$$\nwhere $\\partial_\\xi$ is the [[directional derivative|06KWGHDN2J]] along $\\xi$.\n\n## Remarks\n\nEach term of the sum is the same for $\\alpha$ and $-\\alpha$, so $T_\\xi$ does not depend on the choice of $R_+$.\nThe difference quotient extends smoothly across the hyperplane $\\langle \\alpha, x \\rangle = 0$, so $T_\\xi$ maps homogeneous polynomials of degree $d$ to homogeneous polynomials of degree $d - 1$.\nDunkl's theorem states that $T_\\xi T_\\eta = T_\\eta T_\\xi$ for all $\\xi, \\eta \\in \\R^n$.\nFor $k = 0$, $T_\\xi = \\partial_\\xi$.\n\nExample: $n = 1$, $R = \\set{1, -1}$, $W = \\set{x \\mapsto x, x \\mapsto -x}$ and $k(\\pm 1) = k$.\nThen $T f(x) = f'(x) + k \\frac{f(x) - f(-x)}{x}$.\nFor $f(x) = x^m$, the quotient is $(1 - (-1)^m) x^{m-1}$, so $T x^m = m x^{m-1}$ for even $m$ and $T x^m = (m + 2k) x^{m-1}$ for odd $m$.\n\nNon-example: the operator $f \\mapsto f'(x) + k \\frac{f(x)}{x}$ on $\\R$ is not a Dunkl operator for $k \\ne 0$.\nIt lacks the reflected term $f(-x)$, and it does not even map the constant $1$ to a polynomial.\n\nThe Dunkl Laplacian $\\sum_{i=1}^n T_{e_i}^2$ reduces to the Laplacian when $k = 0$.\n",
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