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  "body": "\n## Summary\n\nIn [[operational calculus|8050R3Z6HA]], $p$ denotes the operator $d/dt$ that sends a function of time to its [[derivative|0V1EJCT8G6]].\nIt is treated as an algebraic symbol: one forms polynomials and fractions in $p$, and $1/p$ is integration from $0$.\nBecause $p$ undoes integration but integration does not quite undo $p$, initial values appear in the rules, as in $p^{-1} p f = f - f(0)$.\n\n## Explanations\n\n### L1 human\n\nWriting $p$ for \"take the derivative\" lets one write $y'' + 3y' + 2y$ as $(p^2 + 3p + 2) y$, and even factor it as $(p + 1)(p + 2) y$.\nIts partner $1/p$ means \"integrate from $0$\".\nDifferentiating an integral gives back the function, but integrating a derivative from $0$ loses the starting value.\nFor example, for $f(t) = t + 5$, integrating $f' = 1$ from $0$ gives $t$, not $t + 5$.\n",
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