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  "body": "\n## Definition\n\nLet $n \\ge 2$ and let $\\Omega \\subseteq \\R^n$ be a connected [[open set|02BH3MCBQB]].\nA *potential* on $\\Omega$ is a function $u$ on $\\Omega$ such that:\n\n1. $u$ is [[superharmonic|X4V2S56YQQ]] on $\\Omega$.\n2. $u \\ge 0$ on $\\Omega$.\n3. The greatest harmonic minorant of $u$ is $0$; equivalently, every [[harmonic function|0DEB0JMN0W]] $h$ on $\\Omega$ with $h \\le u$ satisfies $h \\le 0$.\n\n## Remarks\n\nSince $u \\ge 0$, the function $0$ is a harmonic minorant, so the greatest harmonic minorant exists; it is $-h_0$, where $h_0$ is the [[least harmonic majorant|G0H97JZRS9]] of $-u$.\nLet $\\Omega$ have a Green function $G$.\nThen the [[Riesz decomposition theorem|CBZ20SS8RQ]] shows that the potentials are exactly the functions $x \\mapsto \\int G(x, y)\\, d\\mu(y)$.\nHere $\\mu$ runs over the positive measures for which this function is not identically $+\\infty$.\nEvery nonnegative superharmonic function is uniquely the sum of a potential and a nonnegative harmonic function.\n\nExample: for $n \\ge 3$ let $u(x) = \\abs{x}^{2-n}$ on $\\Omega = \\R^n$, with $u(0) = +\\infty$.\nIt is superharmonic and positive.\nLet $h$ be harmonic with $h \\le u$, and fix $a$.\nBy the [[mean value property|0HYPR64JM2]], $h(a)$ is the mean of $h$ over the sphere $S(a, R)$, which is at most the mean of $u$ there, namely $\\max(\\abs{a}, R)^{2-n}$.\nLetting $R \\to \\infty$ gives $h(a) \\le 0$, so $u$ is a potential.\n\nNon-example: on a bounded domain the constant $u = 1$ is superharmonic and nonnegative, but $h = 1$ is a harmonic minorant with $h \u003e 0$, so clause 3 fails.\n",
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