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  "body": "\n## Definition\n\nLet $f \\colon [0, \\infty) \\to \\C$ be integrable on each interval $[0, T]$ with $T \u003e 0$.\nThe *abscissa of convergence* of the [[Laplace transform|05XT5AVJBK]] of $f$ is\n$$\\sigma_c = \\inf \\set{ \\sigma \\in \\R : \\int_0^\\infty f(t) e^{-\\sigma t}\\, dt \\text{ converges} } \\in [-\\infty, +\\infty],$$\nwhere convergence is that of the [[improper integral|0VCTBJMEJF]] $\\lim_{T \\to \\infty} \\int_0^T f(t) e^{-\\sigma t}\\, dt$, and $\\inf \\emptyset = +\\infty$.\n\n## Remarks\n\nIf the Laplace integral converges at a complex number $s_0$, it converges at every $s$ with $\\operatorname{Re} s \u003e \\operatorname{Re} s_0$.\nHence the integral converges for $\\operatorname{Re} s \u003e \\sigma_c$ and diverges for $\\operatorname{Re} s \u003c \\sigma_c$.\nExample: for $f(t) = e^{at}$ with $a \\in \\R$, $\\int_0^T e^{(a - \\sigma)t}\\, dt$ has a finite limit exactly when $\\sigma \u003e a$, so $\\sigma_c = a$.\nNon-example of a finite value: for $f(t) = e^{t^2}$ the integral diverges for every real $\\sigma$, so $\\sigma_c = +\\infty$; for $f(t) = e^{-t^2}$ it converges for every real $\\sigma$, so $\\sigma_c = -\\infty$.\nFor $f = 1$, $\\sigma_c = 0$, and on the line $\\operatorname{Re} s = 0$ the integral diverges at every point.\n",
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