{
  "aliases": null,
  "backlinks": null,
  "body": "\n## Statement\n\nLet $a$ and $b$ be complex numbers such that neither $a + b + \\frac12$ nor $2a + 2b$ lies in $\\set{0, -1, -2, \\dots}$.\nThen for every complex $x$ with $\\abs{x} \u003c 1$,\n$$\\left[ {}_2F_1\\left( a, b; a + b + \\tfrac12; x \\right) \\right]^2 = {}_3F_2\\left( \\begin{matrix} 2a,\\ 2b,\\ a + b \\\\ a + b + \\frac12,\\ 2a + 2b \\end{matrix} ; x \\right),$$\nwhere ${}_2F_1$ is the [[hypergeometric function|463X5V31D9]] and ${}_3F_2$ is the [[generalized hypergeometric series|VDBAW9PN88]].\n\n## Remarks\n\nOne proof compares differential equations.\nIf $y$ solves a second order linear equation, then $y^2$ solves a third order linear equation, the symmetric square.\nFor the hypergeometric equation with $c = a + b + \\frac12$, the symmetric square turns out to be the generalized hypergeometric equation of the ${}_3F_2$ on the right.\nBoth sides are analytic at $0$ with value $1$, and that equation has only one such solution, so they agree.\nCheck of the first coefficient: on the left, the coefficient of $x$ is $\\frac{2ab}{a + b + \\frac12}$.\nOn the right it is $\\frac{2a \\cdot 2b \\cdot (a + b)}{(a + b + \\frac12)(2a + 2b)} = \\frac{2ab}{a + b + \\frac12}$, as it should be.\nFor $a = b = \\frac14$ the formula reads ${}_2F_1(\\frac14, \\frac14; 1; x)^2 = {}_3F_2(\\frac12, \\frac12, \\frac12; 1, 1; x)$.\nThe relation $c = a + b + \\frac12$ between the parameters is what makes the symmetric square equation hypergeometric, and the proof uses it.\n\n## Explanations\n\n### L1 human\n\nClausen's formula says that the square of a certain hypergeometric function is again a hypergeometric function, with one more parameter.\nSquaring a power series normally mixes the coefficients in a complicated way.\nHere the coefficients of the square come out as a simple ratio of rising factorials.\n\n### L2 human\n\nThe formula links two levels of the hypergeometric hierarchy, ${}_2F_1$ and ${}_3F_2$.\nIt gives positivity results: when the ${}_2F_1$ is real, the ${}_3F_2$ on the right is a square, hence nonnegative.\nIt is also used to turn identities for squares of elliptic integrals into series for $1/\\pi$.\n",
  "commit": "ff8a40749dc16545e3d2fc637f6b0196e81d0bfa",
  "front": {
    "about": [
      "463X5V31D9",
      "VDBAW9PN88"
    ],
    "kind": "statement",
    "msc": [
      "33C20",
      "33C05"
    ],
    "name": "Clausen's formula",
    "role": "theorem",
    "same_as": {
      "wikidata": "Q5129539",
      "wikipedia": "Clausen's formula"
    },
    "sources": [
      {
        "url": "https://en.wikipedia.org/wiki/Clausen%27s_formula"
      }
    ],
    "tag": "M2V5A38W5C",
    "uses": [
      "463X5V31D9",
      "VDBAW9PN88"
    ]
  },
  "kind": "statement",
  "link": "https://tamnd.github.io/math2/node/M2V5A38W5C/",
  "links": [
    {
      "field": "about",
      "target": "463X5V31D9"
    },
    {
      "field": "about",
      "target": "VDBAW9PN88"
    },
    {
      "field": "uses",
      "target": "463X5V31D9"
    },
    {
      "field": "uses",
      "target": "VDBAW9PN88"
    }
  ],
  "markdown": "https://tamnd.github.io/math2/node/M2V5A38W5C.md",
  "msc": [
    "33C20",
    "33C05"
  ],
  "name": "Clausen's formula",
  "prov": null,
  "role": "theorem",
  "source": "https://github.com/tamnd/math2/blob/main/nodes/M2V/M2V5A38W5C.md",
  "status": null,
  "tag": "M2V5A38W5C",
  "uri": "m2://M2V5A38W5C",
  "url": "https://tamnd.github.io/math2/wiki/clausens-formula/",
  "writing": {
    "tag": "M2V5A38W5C",
    "kind": "statement",
    "level": "W0",
    "next": [
      {
        "what": "an inventory row",
        "note": "the row of the inventory that the node accounts for",
        "have": 0,
        "want": 1
      },
      {
        "what": "a source with a locator",
        "have": 0,
        "want": 1
      }
    ]
  }
}
