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  "body": "\n## Definition\n\nLet $G$ be a connected real or complex [[Lie group|7JBRGCVJRB]], and let $\\mathfrak{g}$ be its Lie algebra.\nThe group $G$ is a *simple Lie group* if $\\mathfrak{g}$ is a simple Lie algebra, that is:\n\n1. $\\mathfrak{g}$ is not abelian, and\n2. the only ideals of $\\mathfrak{g}$ are $0$ and $\\mathfrak{g}$.\n\n## Remarks\n\nExample: $G = SU(2)$, with Lie algebra $\\mathfrak{su}(2) \\cong \\R^3$ and the cross product as bracket.\nThe bracket is not identically zero, so clause 1 holds.\nIf an ideal $I$ contains $x \\ne 0$, it contains $x \\times y$ for all $y$, and these vectors fill the plane $x^\\perp$.\nThe cross product of two independent vectors of that plane is a nonzero multiple of $x$, so $I = \\R^3$, and clause 2 holds.\n\nNon-example: $G = U(n)$ with $n \\ge 2$.\nIts Lie algebra $\\mathfrak{u}(n)$ of skew-Hermitian matrices contains the ideal $i\\R\\, I_n$ of scalar matrices, which is neither $0$ nor $\\mathfrak{u}(n)$, so clause 2 fails.\nFor $n = 1$ the group $U(1)$ is abelian, so clause 1 fails.\n\nFor connected $G$, the connected normal Lie subgroups of $G$ correspond to the ideals of $\\mathfrak{g}$.\nSo $G$ is simple exactly when it is not abelian and has no connected normal Lie subgroups other than $\\set{e}$ and $G$.\nA simple Lie group may have a nontrivial discrete centre, so it need not be a simple group in the sense of abstract group theory.\nSome authors also require the centre to be trivial or finite.\n",
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