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  "body": "\n## Statement\n\nLet $n$ be an integer and let $J_n$ be the [[Bessel function of the first kind|CZCMRDWDYW]] of order $n$.\nThen for every $z \\in \\C$,\n$$J_n(z) = \\frac{1}{\\pi} \\int_0^\\pi \\cos(n\\tau - z \\sin \\tau)\\, d\\tau.$$\n\n## Remarks\n\nThe generating function $\\exp\\left( \\frac{z}{2} (t - t^{-1}) \\right) = \\sum_{k \\in \\Z} J_k(z)\\, t^k$ with $t = e^{i\\tau}$ gives $e^{iz \\sin \\tau} = \\sum_{k} J_k(z)\\, e^{ik\\tau}$, the [[Jacobi–Anger expansion|KFHYQM8T7E]].\nSo $J_n(z)$ is the $n$-th Fourier coefficient $\\frac{1}{2\\pi} \\int_{-\\pi}^{\\pi} e^{i(z \\sin \\tau - n\\tau)}\\, d\\tau$.\nWriting $e^{i(z \\sin \\tau - n\\tau)} = \\cos(n\\tau - z\\sin\\tau) - i \\sin(n\\tau - z\\sin\\tau)$, the sine term is odd in $\\tau$ and the cosine term is even, which gives the formula on $[0, \\pi]$.\nExample: for $n = 0$ and $z = 0$ the integral is $\\frac{1}{\\pi} \\int_0^\\pi 1\\, d\\tau = 1 = J_0(0)$.\nThe hypothesis that $n$ is an integer is needed: for non-integer $\\nu$ the same integral defines the Anger function, which differs from $J_\\nu$.\nFor $\\Re z \u003e 0$ and any $\\nu$, Schläfli's extension reads $J_\\nu(z) = \\frac{1}{\\pi} \\int_0^\\pi \\cos(\\nu\\tau - z \\sin\\tau)\\, d\\tau - \\frac{\\sin(\\nu\\pi)}{\\pi} \\int_0^\\infty e^{-z \\sinh t - \\nu t}\\, dt$.\n\n## Explanations\n\n### L1 human\n\nThis formula writes a Bessel function as an average of a cosine over half a turn.\nIt was Bessel's own definition, coming from a problem in planetary motion.\nIt shows at once that $\\abs{J_n(x)} \\le 1$ for real $x$, since the integrand lies between $-1$ and $1$.\n\n### L2 human\n\nThe integral turns many questions about $J_n$ into questions about an oscillatory integral.\nApplying stationary phase to it gives the large-$x$ asymptotics of $J_n(x)$.\nDifferentiating under the integral sign checks Bessel's equation directly.\nIt is also the bridge between Bessel functions and Fourier series of $e^{iz\\sin\\tau}$, which is how they enter Kepler's equation and frequency modulation.\n",
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