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  "body": "\n## Statement\n\nLet $R$ be a ring and let $M$ be a [[simple|G00C22AEDH]] left $R$-module.\nThen the [[endomorphism ring|AWSBZWWMG9]] $\\End_R(M)$ is a [[division ring|0EA5BTA0CX]].\n\n## Remarks\n\n$\\End_R(M)$ is nonzero, since $M \\ne 0$ gives $\\id_M \\ne 0$.\nBy [[Schur's lemma|X4M2FFKQJ6]] every nonzero endomorphism of $M$ is an isomorphism, so its inverse map is again an endomorphism and is its inverse in $\\End_R(M)$.\nExample: $\\End_\\Z(\\Z/p\\Z) \\cong \\Z/p\\Z$, a field, for $p$ prime.\nSimplicity is needed: for the semisimple $\\Z$-module $M = \\Z/p\\Z \\oplus \\Z/p\\Z$, the ring $\\End_\\Z(M) \\cong M_2(\\Z/p\\Z)$ has the nonzero non-invertible element $E_{11}$.\nIf $R$ is an algebra over an algebraically closed field $k$ and $M$ has finite dimension over $k$, then $\\End_R(M) = k$.\n\n## Explanations\n\n### L1 human\n\nThe self-maps of a simple module that are not zero can always be undone.\nSo the self-maps form a ring in which one can divide by every nonzero element, just as in a field, except that the order of multiplication may matter.\n\n### L2 human\n\nThis is how division rings enter the structure theory of rings.\nIn the Artin–Wedderburn theorem, a simple Artinian ring is a matrix ring over the division ring $\\End_R(M)^{\\mathrm{op}}$ for a simple module $M$.\nIn representation theory over $\\C$, it says that endomorphisms of a finite-dimensional irreducible representation are scalars.\n",
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