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  "body": "\n## Statement\n\nLet $f \\colon \\R \\to \\R$ be an [[additive function|KF719SZD5T]], that is, $f(x + y) = f(x) + f(y)$ for all $x, y \\in \\R$.\nAssume that $f$ is [[measurable|YYNCJSR0PJ]] with respect to [[Lebesgue measure|2Z2QVWZ262]].\nThen there is a constant $c \\in \\R$ such that $f(x) = cx$ for all $x \\in \\R$, and in fact $c = f(1)$.\n\n## Remarks\n\nThe proof reduces the claim to boundedness on an interval.\nBy Lusin's theorem, $f$ is bounded on some compact set $K$ of positive measure.\nBy the Steinhaus theorem, the difference set $K - K$ contains an open interval around $0$.\nEach point $x = a - b$ of that interval with $a, b \\in K$ has $f(x) = f(a) - f(b)$, so $f$ is bounded on this interval.\nThen [[Darboux's theorem on additive functions|2F30ZHN1RT]] gives $f(x) = cx$.\nMeasurability cannot be dropped: [[a Hamel basis gives additive functions that are not linear|FFTNS66XG6]], and such functions are not Lebesgue measurable.\nThis is one of the regularity conditions that settle [[Cauchy's functional equation|ZBMEVWN100]].\n\n## Explanations\n\n### L1 human\n\nAn additive function turns sums into sums.\nThe only additive functions one can draw are the lines $f(x) = cx$ through the origin.\nThis theorem says that already a very weak regularity, measurability, forces an additive function to be such a line.\nSo the strange additive functions can never be measured or integrated.\n\n### L2 human\n\nMeasurability is weaker than continuity, monotonicity or local boundedness, so this result contains the other classical criteria.\nIn practice, any additive function that comes from an explicit formula, a limit of continuous functions or a probability model is measurable, so it is linear.\nThe same argument works for additive maps between $\\R^n$ and $\\R^m$.\nMore generally, a Haar measurable homomorphism between second countable locally compact groups is continuous.\nThe key tools, Lusin's theorem and the Steinhaus theorem, are standard in measure theory.\n",
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