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  "body": "\n## Example\n\nLet $a \\in \\C$ and $f(t) = e^{at}$ for $t \\ge 0$, an [[exponential function|0RMVS7RXZX]].\nIts [[Laplace transform|05XT5AVJBK]] is\n$$\\mathcal{L}\\{e^{at}\\}(s) = \\frac{1}{s - a} \\quad (\\operatorname{Re} s \u003e \\operatorname{Re} a).$$\nCheck: for $s \\ne a$ and $T \u003e 0$,\n$$\\int_0^T e^{at} e^{-st}\\, dt = \\frac{1 - e^{-(s - a)T}}{s - a}.$$\nSince $\\abs{e^{-(s - a)T}} = e^{-\\operatorname{Re}(s - a) T}$, this tends to $0$ as $T \\to \\infty$ exactly when $\\operatorname{Re} s \u003e \\operatorname{Re} a$, which gives the formula.\nWhen $\\operatorname{Re} s \u003c \\operatorname{Re} a$ the term $e^{-(s-a)T}$ grows without bound.\nWhen $\\operatorname{Re} s = \\operatorname{Re} a$ it stays on the unit circle without a limit (or the integrand is $1$ if $s = a$), so the integral diverges.\nSo the abscissa of convergence is $\\operatorname{Re} a$.\nThe case $a = 0$ gives $\\mathcal{L}\\{1\\}(s) = 1/s$.\n\n## Explanations\n\n### L1 human\n\nThe exponential $e^{at}$ is the basic building block of Laplace transform tables.\nIts transform $1/(s - a)$ has a single pole at $s = a$, and the location of the pole records the growth rate of $e^{at}$.\nMany other entries, such as those for sine, cosine and hyperbolic functions, follow from this one by linearity.\n",
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