Math 2.0

Algebraic geometry Definition

Enriques surface

Builds on Algebraic surfaceCanonical bundleSheaf cohomologyK3 surface

Definition

Let XX be a smooth projective algebraic surface over ℂ\C, with structure sheaf 𝒪X\mathcal{O}_X and canonical divisor KXK_X. XX is an Enriques surface if:

  1. H1(X,𝒪X)=0H^1(X, \mathcal{O}_X) = 0, that is, the irregularity qq is 00;
  2. H0(X,𝒪X(KX))=0H^0(X, \mathcal{O}_X(K_X)) = 0, that is, the geometric genus pgp_g is 00; and
  3. 2KX2 K_X is linearly equivalent to 00.

Remarks

Clauses 2 and 3 together force KXK_X to be a nonzero element of order 22 in the Picard group, since KX∼0K_X \sim 0 would give pg=1p_g = 1. The double cover X~→X\tilde X \to X defined by KXK_X is unramified, and X~\tilde X is a K3 surface; conversely, the quotient of a K3 surface by a fixed-point-free involution is an Enriques surface. The fundamental group of an Enriques surface is ℤ/2\Z/2, and its Euler characteristic is 1212. Example: in ℙ5\mathbb{P}^5 with coordinates x0,x1,x2,y0,y1,y2x_0, x_1, x_2, y_0, y_1, y_2, let YY be a general intersection of three quadrics Qi(x)+Ri(y)=0Q_i(x) + R_i(y) = 0, i=1,2,3i = 1, 2, 3. Then YY is a K3 surface, and the involution (x,y)↦(x,−y)(x, y) \mapsto (x, -y) acts on YY without fixed points. The quotient of YY by this involution is an Enriques surface. Non-example: a K3 surface satisfies clauses 1 and 3, but it has K∼0K \sim 0 and so pg=1p_g = 1, which fails clause 2. In characteristic 22 the definition is modified, and there are three kinds of Enriques surfaces.

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  1. Algebraic surface concept
  2. Canonical bundle concept
  3. K3 surface concept
  4. Sheaf cohomology concept
  5. Enriques surface definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Enriques_surface
About this page
Tag7H6T24G8BM
URIm2://7H6T24G8BM
Kinddefinition
WritingW0 stub
MSC14J28
DefinesEnriques surface
UsesAlgebraic surface, Canonical bundle, Sheaf cohomology, K3 surface

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