Math 2.0

Dynamical systems and ergodic theory Complex dynamics Conjecture

Eremenko's conjecture

Builds on Entire functionJulia setConnected component

Statement

Let f ⁣:ℂ→ℂf \colon \C \to \C be a transcendental entire function. Let I(f)={z∈ℂ:fn(z)→∞ as n→∞}I(f) = \set{z \in \C : f^n(z) \to \infty \text{ as } n \to \infty} be its escaping set. Then every connected component of I(f)I(f) is unbounded.

Remarks

Eremenko proved that I(f)I(f) is nonempty and that the Julia set of ff is the boundary of I(f)I(f). He also proved that every component of the closure of I(f)I(f) is unbounded. Rippon and Stallard proved in 2005 that I(f)I(f) always has at least one unbounded component. A stronger form, that every escaping point can be joined to ∞\infty by a curve in I(f)I(f), is false. Rottenfußer, Rückert, Rempe and Schleicher gave entire functions whose escaping sets contain no curves at all. In 2021 Martí-Pete, Rempe and Waterman constructed a counterexample to the conjecture itself. For a polynomial of degree at least 22 the analogous statement holds. There the escaping set is the complement of the filled Julia set KK, which is compact and has connected complement. So the escaping set is connected and unbounded.

Reading path

To understand this page from the ground up, read these 4 pages in order. The foundations come first.

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  1. Connected component concept
  2. Entire function concept
  3. Julia set concept
  4. Eremenko's conjecture conjecture

Further reading

  1. Web https://en.wikipedia.org/wiki/Escaping_set
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