Math 2.0

Associative rings and algebras Definition

Filtered algebra

Builds on Associative algebraCommutative ring

Definition

Let KK be a commutative ring and let AA be an associative algebra over KK with unit 11. An (increasing, exhaustive) filtration of AA is a family (Fi)i≥0(F_i)_{i \ge 0} of KK-submodules of AA such that:

  1. Fi⊆Fi+1F_i \subseteq F_{i+1} for all i≥0i \ge 0.
  2. ⋃i≥0Fi=A\bigcup_{i \ge 0} F_i = A.
  3. FiFj⊆Fi+jF_i F_j \subseteq F_{i+j} for all i,j≥0i, j \ge 0.
  4. 1∈F01 \in F_0.

A filtered algebra is an algebra together with such a filtration.

Remarks

The associated graded algebra is gr⁡A=⨁i≥0Fi/Fi−1\operatorname{gr} A = \bigoplus_{i \ge 0} F_i / F_{i-1} with F−1=0F_{-1} = 0; clause 3 makes the product (a+Fi−1)(b+Fj−1)=ab+Fi+j−1(a + F_{i-1})(b + F_{j-1}) = ab + F_{i+j-1} well defined. Example: A=K[x]A = K[x] with FiF_i the polynomials of degree at most ii. Clauses 1, 2 and 4 are clear, and clause 3 holds since deg⁡(fg)≤deg⁡f+deg⁡g\deg(fg) \le \deg f + \deg g. Here gr⁡A≅K[x]\operatorname{gr} A \cong K[x]. Non-example: in K[x]K[x] take F0=K+KxF_0 = K + Kx and FiF_i the polynomials of degree at most i+1i + 1 for i≥1i \ge 1. Clauses 1, 2 and 4 hold, but clause 3 fails: x⋅x=x2∉F0x \cdot x = x^2 \notin F_0. Let U(𝔤)U(\mathfrak{g}) be the universal enveloping algebra of a Lie algebra 𝔤\mathfrak{g} over a field, with FiF_i spanned by products of at most ii elements of 𝔤\mathfrak{g}. Then the Poincaré–Birkhoff–Witt theorem gives gr⁡U(𝔤)≅S(𝔤)\operatorname{gr} U(\mathfrak{g}) \cong S(\mathfrak{g}).

Reading path

To understand this page from the ground up, read these 5 pages in order. The foundations come first.

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  1. Associative algebra concept
  2. Group concept
  3. Ring definition
  4. Commutative ring definition
  5. Filtered algebra definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Filtered_algebra
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Kinddefinition
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MSC16W70
DefinesFiltered algebra
UsesAssociative algebra, Commutative ring

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