Math 2.0

Integral equations Definition

Integral equation of the third kind

Builds on Linear integral equationKernel of an integral equationContinuous function

Definition

Let a<ba < b, let K ⁣:[a,b]×[a,b]→ℂK \colon [a, b] \times [a, b] \to \C be a kernel, let f ⁣:[a,b]→ℂf \colon [a, b] \to \C be given, and let λ∈ℂ\lambda \in \C. Let a0 ⁣:[a,b]→ℂa_0 \colon [a, b] \to \C be a continuous function that has at least one zero in [a,b][a, b] and is not identically zero. An integral equation of the third kind is a linear integral equation of the form a0(x)φ(x)=f(x)+λ∫abK(x,s)φ(s) dsfor all x∈[a,b],a_0(x) \varphi(x) = f(x) + \lambda \int_a^b K(x, s) \varphi(s) \, ds \quad \text{for all } x \in [a, b], for the unknown function φ ⁣:[a,b]→ℂ\varphi \colon [a, b] \to \C.

Remarks

Example: xφ(x)=x+∫−11s φ(s) dsx \varphi(x) = x + \int_{-1}^{1} s \, \varphi(s) \, ds on [−1,1][-1, 1], with a0(x)=xa_0(x) = x, f(x)=xf(x) = x, K(x,s)=sK(x, s) = s and λ=1\lambda = 1. The coefficient a0a_0 is continuous, vanishes at 00, and is not identically zero. The function φ=1\varphi = 1 is a solution, since ∫−11s ds=0\int_{-1}^{1} s \, ds = 0.

Non-example: (2+x)φ(x)=f(x)+∫−11φ(s) ds(2 + x) \varphi(x) = f(x) + \int_{-1}^{1} \varphi(s) \, ds on [−1,1][-1, 1] is not of the third kind, since 2+x2 + x has no zero there. Dividing by 2+x2 + x turns it into an equation of the second kind.

Some authors also allow the upper limit xx in place of bb.

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  1. Continuous function concept
  2. Kernel of an integral equation concept
  3. Linear integral equation concept
  4. Integral equation of the third kind definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Integral_equation
About this page
TagMZHSEZDK3E
URIm2://MZHSEZDK3E
Kinddefinition
WritingW0 stub
MSC45A05, 45H05
DefinesIntegral equation of the third kind
UsesLinear integral equation, Kernel of an integral equation, Continuous function

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