Math 2.0

Geometry Definition

Laguerre plane

Builds on Incidence structure

Definition

Let (𝒫,𝒡,∈)(\mathcal{P}, \mathcal{Z}, \in) be an incidence structure of points and circles, where circles are subsets of 𝒫\mathcal{P}. Let βˆ₯\parallel be an equivalence relation on 𝒫\mathcal{P}, called parallelism. The structure is a Laguerre plane if:

  1. any three pairwise non-parallel points lie on exactly one circle;
  2. for every circle zz, every point P∈zP \in z and every point Qβˆ‰zQ \notin z with Pβˆ₯ΜΈQP \not\parallel Q, there is exactly one circle zβ€²z' with P,Q∈zβ€²P, Q \in z' and z∩zβ€²={P}z \cap z' = \set{P};
  3. for every circle zz and every point PP, there is exactly one point Pβ€²βˆˆzP' \in z with Pβˆ₯Pβ€²P \parallel P';
  4. every circle has at least three points, and there is a circle zz and a point not on zz.

Remarks

Example: the real parabola model has points ℝ2\R^2, parallel classes the vertical lines x=constx = \text{const}, and circles the graphs y=ax2+bx+cy = ax^2 + bx + c with a,b,cβˆˆβ„a, b, c \in \R. Clause 3 holds because each circle is the graph of a function of xx. Clause 1 holds because through three points with distinct xx-coordinates there is exactly one polynomial of degree at most 22. For clause 2, two such polynomials whose graphs touch at P=(x0,y0)P = (x_0, y_0) differ by Ξ»(xβˆ’x0)2\lambda (x - x_0)^2, and exactly one value of Ξ»\lambda makes the graph pass through QQ.

Non-example: keep the same circles but let parallelism be equality of points. Then three points on a vertical line are pairwise non-parallel and lie on no circle, so clause 1 fails.

The classical model is the set of plane sections of a circular cylinder not parallel to its axis, with the generators of the cylinder as parallel classes. More generally, an oval cone in three-dimensional projective space with its vertex removed gives an ovoidal Laguerre plane.

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Further reading

  1. Web https://en.wikipedia.org/wiki/Laguerre_plane
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