Math 2.0

Statistics Definition

Minimax estimator

Builds on Risk functionEstimatorBinomial distribution

Definition

Let {Pθ:θ∈Θ}\set{P_\theta : \theta \in \Theta} be a statistical model with a loss function, and let R(θ,δ)R(\theta, \delta) be the risk function of an estimator δ\delta. The minimax risk of the problem is R∗=inf⁡δsup⁡θ∈ΘR(θ,δ),R^* = \inf_{\delta} \sup_{\theta \in \Theta} R(\theta, \delta), where the infimum is over all estimators. An estimator δ∗\delta^* is minimax if sup⁡θ∈ΘR(θ,δ∗)=R∗.\sup_{\theta \in \Theta} R(\theta, \delta^*) = R^*.

Remarks

A minimax estimator need not exist, and it need not be unique. A Bayes estimator whose risk function is constant in θ\theta is minimax.

Example: let XX be binomial with parameters nn and θ∈[0,1]\theta \in [0, 1], with squared error loss. Let δ∗(X)=(X+n/2)/(n+n)\delta^*(X) = (X + \sqrt{n}/2)/(n + \sqrt{n}). A direct computation of variance plus squared bias gives R(θ,δ∗)=14(1+n)2R(\theta, \delta^*) = \frac{1}{4(1 + \sqrt{n})^2} for every θ\theta. This δ∗\delta^* is the Bayes estimator for the beta prior with parameters n/2\sqrt{n}/2 and n/2\sqrt{n}/2, and its risk is constant, so it is minimax.

Non-example: δ(X)=X/n\delta(X) = X/n in the same problem. Its risk is θ(1−θ)/n\theta(1 - \theta)/n, with maximum 14n\frac{1}{4n} at θ=12\theta = \frac{1}{2}. Since 14n>14(1+n)2\frac{1}{4n} > \frac{1}{4(1 + \sqrt{n})^2}, its worst-case risk exceeds R∗R^*, so it is not minimax.

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  1. Binomial distribution concept
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  3. Risk function concept
  4. Minimax estimator definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Minimax_estimator
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