Math 2.0

Order, lattices, ordered algebraic structures Definition

Successor order

Builds on Partial orderSuccessor function

Definition

Let (P,≤)(P, \le) be a partially ordered set, and write a<ba < b when a≤ba \le b and a≠ba \ne b. A successor order on PP is a map succ⁡ ⁣:P→P\operatorname{succ} \colon P \to P such that:

  1. a≤succ⁡(a)a \le \operatorname{succ}(a) for all a∈Pa \in P.
  2. If succ⁡(a)≤a\operatorname{succ}(a) \le a, then aa is a maximal element of PP.
  3. If a<ba < b, then succ⁡(a)≤b\operatorname{succ}(a) \le b.

Remarks

When aa is not maximal, the clauses say that succ⁡(a)\operatorname{succ}(a) is the least element of {b∈P:a<b}\set{b \in P : a < b}; when aa is maximal, succ⁡(a)=a\operatorname{succ}(a) = a. So the map, if it exists, is unique.

Example: ℤ\Z with succ⁡(n)=n+1\operatorname{succ}(n) = n + 1. Check: n≤n+1n \le n + 1; the inequality n+1≤nn + 1 \le n never holds, so clause 2 is empty; and n<mn < m for integers means n+1≤mn + 1 \le m. On ℕ\N this is the successor function.

Non-example: ℚ\Q with the usual order has no successor order. No rational is maximal, so clauses 1 and 2 force a<succ⁡(a)a < \operatorname{succ}(a); then b=(a+succ⁡(a))/2b = (a + \operatorname{succ}(a))/2 satisfies a<b<succ⁡(a)a < b < \operatorname{succ}(a), which breaks clause 3.

The dual notion is a predecessor order. In Mathlib this is the class SuccOrder.

Reading path

To understand this page from the ground up, read these 3 pages in order. The foundations come first.

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  1. Partial order concept
  2. Successor function concept
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Further reading

  1. Web https://en.wikipedia.org/wiki/Successor_function
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Kinddefinition
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MSC06A06, 06A05
DefinesSuccessor order
UsesPartial order, Successor function

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