Math 2.0

General algebraic systems Terms, identities and equational logic Problem

Tarski's high school algebra problem

Builds on IdentityEquational basisEquational logic

Problem

Consider the signature with a constant 11 and binary operations ++, ⋅\cdot and exponentiation xyx^y, interpreted in the positive integers. Let HSI\mathrm{HSI} be the following eleven identities:

  1. x+y≈y+xx + y \approx y + x and (x+y)+z≈x+(y+z)(x + y) + z \approx x + (y + z);
  2. x⋅1≈xx \cdot 1 \approx x, x⋅y≈y⋅xx \cdot y \approx y \cdot x and (x⋅y)⋅z≈x⋅(y⋅z)(x \cdot y) \cdot z \approx x \cdot (y \cdot z);
  3. x⋅(y+z)≈x⋅y+x⋅zx \cdot (y + z) \approx x \cdot y + x \cdot z;
  4. 1x≈11^x \approx 1, x1≈xx^1 \approx x, xy+z≈xy⋅xzx^{y + z} \approx x^y \cdot x^z, (x⋅y)z≈xz⋅yz(x \cdot y)^z \approx x^z \cdot y^z and (xy)z≈xy⋅z(x^y)^z \approx x^{y \cdot z}.

The problem asks whether every identity in this signature that holds in the positive integers can be derived from HSI\mathrm{HSI} in equational logic.

Remarks

The answer is no. Alex Wilkie found, around 1980, an identity true in the positive integers that cannot be derived from HSI\mathrm{HSI}. Later, R. Gurevič showed that the identities true in the positive integers with 11, ++, ⋅\cdot and exponentiation have no finite equational basis at all. Every identity without exponentiation that holds in the positive integers is derivable from the identities in items 1 to 3. Indeed, both sides expand to the same polynomial; this is why the question was natural.

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Further reading

  1. Web https://en.wikipedia.org/wiki/Tarski%27s_high_school_algebra_problem, Statement of the problem
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