Math 2.0

Geometry Triangles and circles Theorem

Apollonius's theorem

Builds on Median of a triangleMidpointEuclidean distance

Statement

Let AA, BB and CC be points of the Euclidean space ℝn\mathbb{R}^n, and let DD be the midpoint of BB and CC. Let ∣XY∣|XY| denote the distance between the points XX and YY. Then ∣AB∣2+∣AC∣2=2(∣AD∣2+∣BD∣2).|AB|^2 + |AC|^2 = 2 \left( |AD|^2 + |BD|^2 \right).

Remarks

For a triangle ABCABC with the side lengths a=∣BC∣a = |BC|, b=∣CA∣b = |CA|, c=∣AB∣c = |AB|, the median from AA thus has the length ma=122b2+2c2−a2m_a = \frac{1}{2} \sqrt{2 b^2 + 2 c^2 - a^2}. In vector form, with u=B−Au = B - A and v=C−Av = C - A, the statement is the parallelogram law ∥u+v∥2+∥u−v∥2=2∥u∥2+2∥v∥2\|u + v\|^2 + \|u - v\|^2 = 2\|u\|^2 + 2\|v\|^2. For an isosceles triangle with ∣AB∣=∣AC∣|AB| = |AC|, the median ADAD is perpendicular to BCBC, and the theorem reduces to the Pythagorean theorem.

History

The theorem is Proposition 122 of Book VII of the Collection of Pappus of Alexandria. It was possibly in the lost work Plane Loci of Apollonius of Perga.

Reading path

To understand this page from the ground up, read these 4 pages in order. The foundations come first.

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Each page uses the pages above it. The colour of the bar on a box shows how strong the evidence is, and the box also gives it as text. The list has the same pages.
  • no evidence level
  1. Euclidean distance concept
  2. Median of a triangle concept
  3. Midpoint concept
  4. Apollonius's theorem statement

Further reading

  1. Web https://en.wikipedia.org/wiki/Apollonius%27s_theorem, Statement and relation to other theorem
About this page
Tag0NAKHQ9XYY
URIm2://0NAKHQ9XYY
Kindstatement, theorem
WritingW1 stated
MSC51M04
StatusThis copy of the site has no build data. Run m2 status 0NAKHQ9XYY.
UsesMedian of a triangle, Midpoint, Euclidean distance
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