Math 2.0

Combinatorics Enumerative combinatorics: sequences and numbers Theorem

Bertrand's ballot theorem

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Statement

Let pp and qq be natural numbers with p>qp > q. In an election, candidate AA gets pp votes and candidate BB gets qq votes. The votes are counted one at a time, in an order chosen uniformly at random among all orders. Then the probability that AA is strictly ahead of BB after each vote is counted is p−qp+q.\frac{p - q}{p + q}.

Remarks

Equivalently, the number of such counting orders, as words with pp letters AA and qq letters BB, is p−qp+q(p+qp)\frac{p - q}{p + q} \binom{p + q}{p}. Example: for p=3p = 3 and q=1q = 1, the probability is 12\frac{1}{2}. Of the 44 orders, AAABAAAB and AABAAABA work. A short proof uses the reflection principle for lattice paths.

History

William Allen Whitworth published the result in 1878. Joseph Bertrand found it again in 1887, and the theorem has his name.

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  1. Binomial coefficient definition
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Further reading

  1. Web https://en.wikipedia.org/wiki/Bertrand's_ballot_theorem, lead section
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