Number theory Divisibility and primes Theorem
Bézout's identity
Builds on Greatest common divisor
Statement
Let and be integers, and let be their greatest common divisor. Then there are integers and such that .
Remarks
The integers and are not unique. If is a solution, then is also a solution for each integer , when . The set of all integers is the set of the multiples of . The extended Euclidean algorithm computes one pair . For example, and .
Reading path
To understand this page from the ground up, read these 3 pages in order. The foundations come first.
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- no evidence level
- Divisibility definition
- Greatest common divisor definition
- Bézout's identity statement
Where this leads
3 pages build on this one.
Further reading
About this page
| Tag | 0DQVHMYAGA |
|---|---|
| URI | m2://0DQVHMYAGA |
| Aliases | bezout-lemma, bezouts-lemma |
| Kind | statement, theorem |
| Writing | W1 stated |
| MSC | 11A05 |
| Status | This copy of the site has no build data. Run m2 status 0DQVHMYAGA. |
| Uses | Greatest common divisor |
| Same as |
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What this page needs for W2
- edge about out: the concepts that the statement is about (0 of 1)
- edge proves in: at least one proof node (0 of 1)
- edge instance_of or illustrates in: one example that shows the statement at work (0 of 1)
- explanation L2 (0 of 1)
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