Math 2.0

Number theory Divisibility and primes Theorem

Bézout's identity

Builds on Greatest common divisor

Statement

Let aa and bb be integers, and let d=gcd⁡(a,b)d = \gcd(a, b) be their greatest common divisor. Then there are integers xx and yy such that ax+by=da x + b y = d.

Remarks

The integers xx and yy are not unique. If (x,y)(x, y) is a solution, then (x+kb/d,  y−ka/d)(x + k b / d, \; y - k a / d) is also a solution for each integer kk, when d≠0d \neq 0. The set of all integers ax+bya x + b y is the set of the multiples of dd. The extended Euclidean algorithm computes one pair (x,y)(x, y). For example, gcd⁡(12,42)=6\gcd(12, 42) = 6 and 12⋅(−3)+42⋅1=612 \cdot (-3) + 42 \cdot 1 = 6.

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  1. Divisibility definition
  2. Greatest common divisor definition
  3. Bézout's identity statement

Where this leads

3 pages build on this one.

Further reading

  1. Web https://en.wikipedia.org/wiki/B%C3%A9zout%27s_identity, lead section
About this page
Tag0DQVHMYAGA
URIm2://0DQVHMYAGA
Aliasesbezout-lemma, bezouts-lemma
Kindstatement, theorem
WritingW1 stated
MSC11A05
StatusThis copy of the site has no build data. Run m2 status 0DQVHMYAGA.
UsesGreatest common divisor
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