Math 2.0

Combinatorics Theorem

Closed formula for Catalan numbers

Builds on Binomial coefficientCentral binomial coefficientCatalan numbers

Statement

Let nn be a natural number, and let CnC_n be the nn-th Catalan number. Then Cn=1n+1(2nn)=(2n)!(n+1)! n!.C_n = \frac{1}{n + 1} \binom{2n}{n} = \frac{(2n)!}{(n + 1)!\, n!}.

Remarks

The fraction is an integer, because Cn=(2nn)−(2nn+1)C_n = \binom{2n}{n} - \binom{2n}{n+1}. The numerator (2nn)\binom{2n}{n} is the central binomial coefficient. Example: C4=15(84)=705=14C_4 = \frac{1}{5} \binom{8}{4} = \frac{70}{5} = 14.

Reading path

To understand this page from the ground up, read these 4 pages in order. The foundations come first.

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Each page uses the pages above it. The colour of the bar on a box shows how strong the evidence is, and the box also gives it as text. The list has the same pages.
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  1. Binomial coefficient definition
  2. Catalan numbers definition
  3. Central binomial coefficient definition
  4. Closed formula for Catalan numbers statement

Further reading

  1. Web https://en.wikipedia.org/wiki/Catalan_number, Proof of the formula
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Tag0NNDQVJ54Q
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Kindstatement, theorem
WritingW0 stub
MSC05A15
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UsesBinomial coefficient, Central binomial coefficient, Catalan numbers

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