Math 2.0

Potential theory Discrete potential theory Problem

Discrete Dirichlet problem

Builds on GraphDiscrete harmonic function

Problem

Let G=(V,E)G = (V, E) be a finite connected graph with symmetric positive edge weights c(x,y)c(x, y). Let B⊆VB \subseteq V be a nonempty set of boundary vertices, and let I=V∖BI = V \setminus B be the set of interior vertices. Let g ⁣:B→ℝg \colon B \to \R be a function. Find a function f ⁣:V→ℝf \colon V \to \R that is harmonic at every vertex of II and satisfies f=gf = g on BB.

Remarks

The problem always has exactly one solution. Uniqueness follows from the maximum principle: the difference hh of two solutions is harmonic on II and zero on BB. At an interior vertex where hh is largest, harmonicity forces the same value at all neighbours. Connectedness spreads this value to a vertex of BB, so max⁡h=0\max h = 0, and in the same way min⁡h=0\min h = 0. The conditions form a square system of ∣I∣\abs{I} linear equations in the ∣I∣\abs{I} unknowns f(x)f(x), x∈Ix \in I, so uniqueness gives existence. The solution has the probabilistic form f(x)=𝔼x[g(Xτ)]f(x) = \mathbb{E}_x\big[g(X_\tau)\big], where (Xn)(X_n) is the random walk with p(x,y)=c(x,y)/c(x)p(x, y) = c(x, y)/c(x) started at xx and τ\tau is its first hitting time of BB. Example: on the path with vertices 0,1,…,n0, 1, \dots, n, unit weights and B={0,n}B = \set{0, n}, the solution is the linear interpolation f(k)=g(0)+kn(g(n)−g(0))f(k) = g(0) + \tfrac{k}{n}\big(g(n) - g(0)\big). Connectedness matters: if a component of the graph does not meet BB, any constant can be added to ff on that component, and the solution is not unique.

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Further reading

  1. Web https://en.wikipedia.org/wiki/Discrete_Laplace_operator
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