Math 2.0

Operator theory Proposition

Eigenspaces of a self-adjoint operator are orthogonal

Builds on Self-adjoint operatorEigenspaceOrthogonal vectors

Statement

Let VV be a finite-dimensional inner product space over ℝ\R or ℂ\C, and let T ⁣:V→VT \colon V \to V be a self-adjoint linear map. Let vv and ww be eigenvectors of TT for distinct eigenvalues λ≠μ\lambda \ne \mu. Then vv and ww are orthogonal. So the eigenspaces of TT for distinct eigenvalues are orthogonal to each other.

Remarks

The proof: λ⟨v,w⟩=⟨T(v),w⟩=⟨v,T(w)⟩=μ⟨v,w⟩\lambda \langle v, w \rangle = \langle T(v), w \rangle = \langle v, T(w) \rangle = \mu \langle v, w \rangle, since μ\mu is real. So (λ−μ)⟨v,w⟩=0(\lambda - \mu) \langle v, w \rangle = 0, and ⟨v,w⟩=0\langle v, w \rangle = 0.

Reading path

To understand this page from the ground up, read these 13 pages in order. The foundations come first.

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Each page uses the pages above it. The colour of the bar on a box shows how strong the evidence is, and the box also gives it as text. The list has the same pages.
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  1. Vector space definition
  2. Inner product definition
  3. Linear map definition
  4. Inner product space definition
  5. Orthogonal vectors definition
  6. Endomorphism definition
  7. Kernel of a linear map definition
  8. Adjoint of a linear map definition
  9. Eigenvalue definition
  10. Eigenvector definition
  11. Self-adjoint operator definition
  12. Eigenspace definition
  13. Eigenspaces of a self-adjoint operator are orthogonal statement

Further reading

  1. Web https://en.wikipedia.org/wiki/Self-adjoint_operator, Properties
About this page
Tag0JHGAV9H25
URIm2://0JHGAV9H25
Kindstatement, proposition
WritingW0 stub
MSC47B15, 15A18
StatusThis copy of the site has no build data. Run m2 status 0JHGAV9H25.
UsesSelf-adjoint operator, Eigenspace, Orthogonal vectors

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