Eigenspaces of a self-adjoint operator are orthogonal
Statement
Let be a finite-dimensional inner product space over or , and let be a self-adjoint linear map. Let and be eigenvectors of for distinct eigenvalues . Then and are orthogonal. So the eigenspaces of for distinct eigenvalues are orthogonal to each other.
Remarks
The proof: , since is real. So , and .
Reading path
To understand this page from the ground up, read these 13 pages in order. The foundations come first.
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- Vector space definition
- Inner product definition
- Linear map definition
- Inner product space definition
- Orthogonal vectors definition
- Endomorphism definition
- Kernel of a linear map definition
- Adjoint of a linear map definition
- Eigenvalue definition
- Eigenvector definition
- Self-adjoint operator definition
- Eigenspace definition
- Eigenspaces of a self-adjoint operator are orthogonal statement
Further reading
About this page
| Tag | 0JHGAV9H25 |
|---|---|
| URI | m2://0JHGAV9H25 |
| Kind | statement, proposition |
| Writing | W0 stub |
| MSC | 47B15, 15A18 |
| Status | This copy of the site has no build data. Run m2 status 0JHGAV9H25. |
| Uses | Self-adjoint operator, Eigenspace, Orthogonal vectors |
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