Math 2.0

Operations research, mathematical programming Linear programming Lemma

Farkas' lemma

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Statement

Let AA be a real m×nm \times n matrix and let b∈ℝmb \in \R^m. For vectors, write v≥0v \ge 0 when every coordinate of vv is nonnegative, and let ATA^T be the transpose of AA. Then exactly one of the following two systems has a solution:

  1. x∈ℝnx \in \R^n with Ax=bA x = b and x≥0x \ge 0;
  2. y∈ℝmy \in \R^m with ATy≥0A^T y \ge 0 and bTy<0b^T y < 0.

Remarks

Both cannot hold: if Ax=bAx = b with x≥0x \ge 0 and ATy≥0A^T y \ge 0, then bTy=xT(ATy)≥0b^T y = x^T (A^T y) \ge 0. For the other direction, the set C={Ax:x≥0}C = \set{Ax : x \ge 0} is the convex cone generated by the columns of AA, and it is closed because it is finitely generated. If b∉Cb \notin C, the hyperplane separation theorem gives a hyperplane through the origin that separates bb from CC; its normal vector yy solves the second system. Example: for A=(1001)A = \begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix} and b=(1,−1)Tb = (1, -1)^T, the first system has no solution, and y=(0,1)Ty = (0, 1)^T solves the second, since ATy=(0,1)T≥0A^T y = (0, 1)^T \ge 0 and bTy=−1<0b^T y = -1 < 0.

Going deeper

For a student

Farkas' lemma is a theorem of the alternative, and it is the basis of the duality theory of linear programming. Many variants follow from it by adding slack variables, for example the version with Ax≤bAx \le b. Gordan's lemma and the Minkowski–Weyl theorem belong to the same circle of ideas about finitely generated cones.

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  1. Convex cone concept
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Further reading

  1. Web https://en.wikipedia.org/wiki/Farkas'_lemma
About this page
TagFYZC634H2D
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Kindstatement, lemma
WritingW0 stub
MSC90C05, 52A20, 15A39
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AboutConvex cone
UsesMatrix, Transpose, Convex cone
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