Math 2.0

Number theory Theorem

Infinitely many primes congruent to 1 modulo n

Builds on Prime numberCongruence modulo n

Statement

Let nn be a positive integer. Then there are infinitely many prime numbers pp such that p≡1(modn)p \equiv 1 \pmod{n}.

Remarks

This is the case a=1a = 1 of Dirichlet's theorem on arithmetic progressions. The case a=1a = 1 has an elementary proof with cyclotomic polynomials. A prime factor pp of Φn(m)\Phi_n(m) that does not divide nn satisfies p≡1(modn)p \equiv 1 \pmod n. For example, the primes p≡1(mod10)p \equiv 1 \pmod{10} start with 11,31,41,61,7111, 31, 41, 61, 71.

Reading path

To understand this page from the ground up, read these 4 pages in order. The foundations come first.

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Each page uses the pages above it. The colour of the bar on a box shows how strong the evidence is, and the box also gives it as text. The list has the same pages.
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  1. Divisibility definition
  2. Congruence modulo n definition
  3. Prime number definition
  4. Infinitely many primes congruent to 1 modulo n statement

Further reading

  1. Web https://en.wikipedia.org/wiki/Dirichlet%27s_theorem_on_arithmetic_progressions, Examples
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Kindstatement, theorem
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