Math 2.0

Measure and integration Problem

Kakeya needle problem

Builds on Lebesgue measure

Problem

A needle is a line segment of length 11 in the plane ℝ2\R^2. Find the smallest area, in the sense of Lebesgue measure, of a region R⊂ℝ2R \subset \R^2 with the following property. The needle can be moved continuously inside RR so that it ends in its starting position with its two ends exchanged.

Remarks

The problem is solved, and the answer is that there is no positive minimum. Abram Besicovitch showed that for every ε>0\varepsilon > 0 there is a region of area less than ε\varepsilon in which the needle can be turned around. His construction builds on a set of measure zero that contains a unit segment in every direction, an example of a Kakeya set. If RR is required to be convex, the minimum exists: it is the equilateral triangle of height 11, of area 1/31/\sqrt{3}, a result of Julius Pál.

Reading path

To understand this page from the ground up, read these 5 pages in order. The foundations come first.

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Each page uses the pages above it. The colour of the bar on a box shows how strong the evidence is, and the box also gives it as text. The list has the same pages.
  • no evidence level
  1. Borel sigma-algebra concept
  2. Euclidean space object
  3. Outer measure concept
  4. Lebesgue measure object
  5. Kakeya needle problem problem

Further reading

  1. Web https://en.wikipedia.org/wiki/Kakeya_set
About this page
TagWZ42B0SAVM
URIm2://WZ42B0SAVM
Kindproblem
WritingW0 stub
MSC28A75, 52A38
StatusThis copy of the site has no build data. Run m2 status WZ42B0SAVM.
AboutKakeya set
UsesLebesgue measure

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