Math 2.0

Integral equations Definition

Laplace transform method for convolution equations

Builds on Volterra equation of convolution typeLaplace transformConvolution theorem for the Laplace transformInverse Laplace transform

Definition

Let kk and ff be locally integrable functions on [0,∞)[0, \infty) whose Laplace transforms k^(p)=∫0∞e−ptk(t) dt\hat k(p) = \int_0^\infty e^{-pt} k(t) \, dt and f^(p)\hat f(p) converge absolutely for Re⁡p>c\operatorname{Re} p > c, for some real cc. Consider the Volterra equation of convolution type x(t)=f(t)+∫0tk(t−s) x(s) ds,t≥0.x(t) = f(t) + \int_0^t k(t - s) \, x(s) \, ds, \quad t \ge 0. The Laplace transform method for this equation consists of the following steps.

  1. Assume that the solution xx has a Laplace transform x^\hat x, and apply the convolution theorem to get x^(p)=f^(p)+k^(p) x^(p)\hat x(p) = \hat f(p) + \hat k(p) \, \hat x(p).
  2. Solve: x^(p)=f^(p)1−k^(p)\hat x(p) = \dfrac{\hat f(p)}{1 - \hat k(p)} for Re⁡p\operatorname{Re} p large enough that k^(p)≠1\hat k(p) \ne 1.
  3. Recover xx as the inverse Laplace transform of x^\hat x, and check that it solves the equation.

For an equation of the first kind ∫0tk(t−s) x(s) ds=f(t)\int_0^t k(t - s) \, x(s) \, ds = f(t), step 2 becomes x^=f^/k^\hat x = \hat f / \hat k.

Remarks

Example: x(t)=t−∫0t(t−s) x(s) dsx(t) = t - \int_0^t (t - s) \, x(s) \, ds, with k(u)=−uk(u) = -u and f(t)=tf(t) = t. Here k^(p)=−1/p2\hat k(p) = -1/p^2 and f^(p)=1/p2\hat f(p) = 1/p^2, so x^(p)=1/p21+1/p2=1p2+1\hat x(p) = \frac{1/p^2}{1 + 1/p^2} = \frac{1}{p^2 + 1} and x=sin⁡x = \sin. Check: ∫0t(t−s)sin⁡s ds=t−sin⁡t\int_0^t (t - s) \sin s \, ds = t - \sin t, so the right side is sin⁡t\sin t. Non-example: the method does not apply directly to x(t)=1+∫0tts x(s) dsx(t) = 1 + \int_0^t ts \, x(s) \, ds, since the kernel tsts is not a function of t−st - s, and the transform of the integral term is not a product. The step 1 assumption is harmless when kk and ff are as above: the unique locally integrable solution then has a Laplace transform for Re⁡p\operatorname{Re} p large. The function rr with r^=k^/(1−k^)\hat r = \hat k / (1 - \hat k) is the resolvent kernel, and x=f+r∗fx = f + r * f.

Reading path

To understand this page from the ground up, read these 7 pages in order. The foundations come first.

Show the path as a graph
Each page uses the pages above it. The colour of the bar on a box shows how strong the evidence is, and the box also gives it as text. The list has the same pages.
  • no evidence level
  1. Function concept
  2. Inverse Laplace transform concept
  3. Laplace transform concept
  4. Volterra equation of convolution type concept
  5. Laplace transform definition
  6. Convolution theorem for the Laplace transform statement
  7. Laplace transform method for convolution equations definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Laplace_transform
About this page
TagXQTHXW4F1R
URIm2://XQTHXW4F1R
Kinddefinition
WritingW0 stub
MSC45D05, 45E10, 44A10
DefinesLaplace transform method for convolution equations
UsesVolterra equation of convolution type, Laplace transform, Convolution theorem for the Laplace transform, Inverse Laplace transform

Markdown · JSON · Edit on GitHub

What this page needs for W1

  • an inventory row: the row of the inventory that the node accounts for (0 of 1)
  • a source with a locator (0 of 1)

The writing levels say how complete the text of a page is. They do not measure its truth.

What links here

No page links to this page yet.