Math 2.0

Combinatorics Basic counting Theorem

Multinomial theorem

Builds on Multinomial coefficient

Statement

Let RR be a commutative ring, let x1,…,xm∈Rx_1, \dots, x_m \in R, and let nn be a natural number. Then (x1+⋯+xm)n=∑k1+⋯+km=n(nk1,…,km)x1k1⋯xmkm.(x_1 + \dots + x_m)^n = \sum_{k_1 + \dots + k_m = n} \binom{n}{k_1, \dots, k_m} x_1^{k_1} \cdots x_m^{k_m}. The sum runs over all mm-tuples (k1,…,km)(k_1, \dots, k_m) of natural numbers with sum nn, and the coefficients are multinomial coefficients.

Remarks

For m=2m = 2 it is the binomial theorem. Example: (x+y+z)2=x2+y2+z2+2xy+2yz+2xz(x + y + z)^2 = x^2 + y^2 + z^2 + 2xy + 2yz + 2xz. With all xi=1x_i = 1 it gives ∑(nk1,…,km)=mn\sum \binom{n}{k_1, \dots, k_m} = m^n.

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Further reading

  1. Web https://en.wikipedia.org/wiki/Multinomial_theorem, Theorem
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