Math 2.0

Combinatorics Basic counting Theorem

Pascal's rule

Builds on Binomial coefficient

Statement

Let nn and kk be natural numbers. Then (n+1k+1)=(nk)+(nk+1).\binom{n+1}{k+1} = \binom{n}{k} + \binom{n}{k+1}.

Remarks

For n=4n = 4 and k=1k = 1 it gives (52)=(41)+(42)=4+6=10\binom{5}{2} = \binom{4}{1} + \binom{4}{2} = 4 + 6 = 10. Combinatorial proof: fix one element xx of an (n+1)(n+1)-element set. A (k+1)(k+1)-subset contains xx, and then it has kk other elements, or it omits xx. The rule builds Pascal's triangle row by row.

Reading path

To understand this page from the ground up, read these 2 pages in order. The foundations come first.

Show the path as a graph
Each page uses the pages above it. The colour of the bar on a box shows how strong the evidence is, and the box also gives it as text. The list has the same pages.
  • no evidence level
  1. Binomial coefficient definition
  2. Pascal's rule statement

Further reading

  1. Web https://en.wikipedia.org/wiki/Pascal's_rule, lead section
About this page
Tag0YRG241HQQ
URIm2://0YRG241HQQ
Kindstatement, theorem
WritingW1 stated
MSC05A10
StatusThis copy of the site has no build data. Run m2 status 0YRG241HQQ.
UsesBinomial coefficient
Same as

Markdown · JSON · Edit on GitHub

What this page needs for W2

  • edge about out: the concepts that the statement is about (0 of 1)
  • edge proves in: at least one proof node (0 of 1)
  • edge instance_of or illustrates in: one example that shows the statement at work (0 of 1)
  • explanation L2 (0 of 1)

The writing levels say how complete the text of a page is. They do not measure its truth.

What links here

No page links to this page yet.