Combinatorics Basic counting Theorem
Pascal's rule
Builds on Binomial coefficient
Statement
Let and be natural numbers. Then
Remarks
For and it gives . Combinatorial proof: fix one element of an -element set. A -subset contains , and then it has other elements, or it omits . The rule builds Pascal's triangle row by row.
Reading path
To understand this page from the ground up, read these 2 pages in order. The foundations come first.
Show the path as a graph
- no evidence level
- Binomial coefficient definition
- Pascal's rule statement
Further reading
- Web https://en.wikipedia.org/wiki/Pascal's_rule, lead section
About this page
| Tag | 0YRG241HQQ |
|---|---|
| URI | m2://0YRG241HQQ |
| Kind | statement, theorem |
| Writing | W1 stated |
| MSC | 05A10 |
| Status | This copy of the site has no build data. Run m2 status 0YRG241HQQ. |
| Uses | Binomial coefficient |
| Same as |
Markdown · JSON · Edit on GitHub
What this page needs for W2
- edge about out: the concepts that the statement is about (0 of 1)
- edge proves in: at least one proof node (0 of 1)
- edge instance_of or illustrates in: one example that shows the statement at work (0 of 1)
- explanation L2 (0 of 1)
The writing levels say how complete the text of a page is. They do not measure its truth.
What links here
No page links to this page yet.