Math 2.0

Functional analysis Proposition

Polarisation identity

Builds on Norm induced by an inner product

Statement

Let VV be an inner product space with the induced norm ∥⋅∥\norm{\cdot}, and let x,y∈Vx, y \in V. If VV is a real space, then ⟨x,y⟩=14(∥x+y∥2−∥x−y∥2).\langle x, y \rangle = \frac{1}{4} \left( \norm{x + y}^2 - \norm{x - y}^2 \right). If VV is a complex space, with the inner product linear in the first argument, then ⟨x,y⟩=14∑k=03ik∥x+iky∥2.\langle x, y \rangle = \frac{1}{4} \sum_{k=0}^{3} i^k \norm{x + i^k y}^2.

Remarks

So the norm determines the inner product. In particular, a linear map that keeps norms also keeps inner products. With the convention of linearity in the second argument, the factor iki^k moves to the other vector, and the complex formula changes accordingly.

Reading path

To understand this page from the ground up, read these 6 pages in order. The foundations come first.

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  1. Vector space definition
  2. Inner product definition
  3. Norm definition
  4. Inner product space definition
  5. Norm induced by an inner product definition
  6. Polarisation identity statement

Where this leads

1 page builds on this one.

Further reading

  1. Web https://en.wikipedia.org/wiki/Polarization_identity, Polarization identities
About this page
Tag05FKHRT0B4
URIm2://05FKHRT0B4
Kindstatement, proposition
WritingW1 stated
MSC46C05, 15A63
StatusThis copy of the site has no build data. Run m2 status 05FKHRT0B4.
UsesNorm induced by an inner product
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