Geometry Triangles and circles Theorem
Routh's theorem
Builds on TriangleArea of a triangle
Statement
Let be a triangle in the Euclidean plane with area . Let , , be points in the interiors of the sides , , , and let , and . Then the three segments , , bound a triangle whose area is When , this triangle degenerates to a point.
Remarks
A proof places the triangle in barycentric coordinates, computes the three intersection points of the cevians, and takes the ratio of determinants. Example: with , the area is , the well-known one-seventh triangle. The case is exactly the condition of Ceva's theorem for the three cevians to be concurrent, and Routh's formula gives area there.
Going deeper
For a student
Routh's theorem refines Ceva's theorem: Ceva says when the inner triangle is a point, and Routh measures it in all other cases. Because affine maps preserve ratios of areas and ratios along lines, it is enough to prove it for one triangle, for example , , . The theorem is a good exercise in barycentric coordinates and in the use of the determinant to compute areas.
Reading path
To understand this page from the ground up, read these 3 pages in order. The foundations come first.
Show the path as a graph
- no evidence level
- Triangle concept
- Area of a triangle concept
- Routh's theorem statement
Further reading
About this page
| Tag | VWQQY7NFED |
|---|---|
| URI | m2://VWQQY7NFED |
| Kind | statement, theorem |
| Writing | W0 stub |
| MSC | 51M04, 51M25 |
| Status | This copy of the site has no build data. Run m2 status VWQQY7NFED. |
| About | Triangle |
| Uses | Triangle, Area of a triangle |
| Same as |
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