Math 2.0

Integral transforms, operational calculus Definition

Spherical mean transform

Builds on SphereIntegral transform

Definition

Let n≥2n \ge 2, let Sn−1={θ∈ℝn:∣θ∣=1}S^{n-1} = \set{\theta \in \R^n : \abs{\theta} = 1} be the unit sphere, let σ\sigma be its surface measure, and let ωn−1=σ(Sn−1)\omega_{n-1} = \sigma(S^{n-1}). Let f ⁣:ℝn→ℂf \colon \R^n \to \C be continuous. The spherical mean transform of ff is the function on ℝn×[0,∞)\R^n \times [0, \infty) given by (Mf)(x,r)=1ωn−1∫Sn−1f(x+rθ) dσ(θ).(M f)(x, r) = \frac{1}{\omega_{n-1}} \int_{S^{n-1}} f(x + r\theta)\, d\sigma(\theta).

Remarks

Mf(x,r)M f(x, r) is the average of ff over the sphere of center xx and radius rr, and Mf(x,0)=f(x)M f(x, 0) = f(x). If ff is of class C2C^2, then MfM f satisfies the Darboux equation ΔxMf(x,r)=(∂2∂r2+n−1r∂∂r)Mf(x,r),r>0.\Delta_x M f(x, r) = \left( \frac{\partial^2}{\partial r^2} + \frac{n - 1}{r} \frac{\partial}{\partial r} \right) M f(x, r), \qquad r > 0.

Example: f(x)=∣x∣2f(x) = \abs{x}^2. Since ∣x+rθ∣2=∣x∣2+2r x⋅θ+r2\abs{x + r\theta}^2 = \abs{x}^2 + 2r\, x \cdot \theta + r^2 and θ↦x⋅θ\theta \mapsto x \cdot \theta has mean 00 over the sphere, Mf(x,r)=∣x∣2+r2M f(x, r) = \abs{x}^2 + r^2. Both sides of the Darboux equation equal 2n2n.

Non-example: f(y)=∣y∣1−nf(y) = \abs{y}^{1-n} for y≠0y \ne 0 and f(0)=0f(0) = 0 is not continuous. Its mean over the sphere of center x≠0x \ne 0 and radius r=∣x∣r = \abs{x}, which passes through 00, is +∞+\infty.

The function ff may also be only locally integrable, and then Mf(x,r)M f(x, r) is defined for almost every (x,r)(x, r).

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Further reading

  1. Web https://en.wikipedia.org/wiki/Spherical_mean
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MSC44A12, 53C65, 35L05
DefinesSpherical mean transform
UsesSphere, Integral transform

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