Math 2.0

Associative rings and algebras Definition

Stably finite ring

Builds on Dedekind-finite ringMatrix ring

Definition

Let RR be a ring with 11. For n≥1n \ge 1, let Mn(R)M_n(R) be the matrix ring of n×nn \times n matrices over RR. The ring RR is stably finite if Mn(R)M_n(R) is Dedekind-finite for every n≥1n \ge 1. That is, for all n≥1n \ge 1 and A,B∈Mn(R)A, B \in M_n(R), the equation AB=InAB = I_n implies BA=InBA = I_n.

Remarks

Example: every commutative ring RR is stably finite. If AB=InAB = I_n in Mn(R)M_n(R), then det⁡(A)det⁡(B)=1\det(A) \det(B) = 1, so AA has the inverse det⁡(A)−1adj⁡(A)\det(A)^{-1} \operatorname{adj}(A), and BA=A−1(AB)A=InBA = A^{-1}(AB)A = I_n.

Non-example: the ring End⁡(V)\End(V) of linear maps on an infinite-dimensional vector space VV is not stably finite, since already M1(End⁡(V))=End⁡(V)M_1(\End(V)) = \End(V) contains a,ba, b with ab=1≠baab = 1 \ne ba.

Taking n=1n = 1 shows that a stably finite ring is Dedekind-finite. The converse fails: there are Dedekind-finite rings RR for which M2(R)M_2(R) is not Dedekind-finite. Equivalently, RR is stably finite if for every n≥1n \ge 1 the left module RnR^n is not isomorphic to Rn⊕NR^n \oplus N for a nonzero module NN. A nonzero stably finite ring has invariant basis number.

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To understand this page from the ground up, read these 3 pages in order. The foundations come first.

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  1. Dedekind-finite ring concept
  2. Matrix ring object
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Further reading

  1. Web https://en.wikipedia.org/wiki/Dedekind-finite_ring
About this page
TagJGVDA1N106
URIm2://JGVDA1N106
Kinddefinition
WritingW0 stub
MSC16U99, 16D40
DefinesStably finite ring
UsesDedekind-finite ring, Matrix ring

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