Math 2.0

Number theory Proposition

Sum of the roots of unity

Builds on Primitive root of unitySum of a finite geometric progression

Statement

Let n≥2n \ge 2 be an integer and let ζ\zeta be a primitive root of unity. Then ∑k=0n−1ζk=1+ζ+ζ2+⋯+ζn−1=0.\sum_{k=0}^{n-1} \zeta^k = 1 + \zeta + \zeta^2 + \dots + \zeta^{n-1} = 0.

Remarks

Proof: ζ≠1\zeta \neq 1, so the geometric sum formula gives ζn−1ζ−1=0\frac{\zeta^n - 1}{\zeta - 1} = 0. Thus the sum of all the nnth roots of unity is 00 for n≥2n \ge 2. For n=1n = 1 the sum is 11.

Reading path

To understand this page from the ground up, read these 6 pages in order. The foundations come first.

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  1. Complex numbers object
  2. Mathematical induction concept
  3. Root of unity definition
  4. Sum of a finite geometric progression statement
  5. Primitive root of unity definition
  6. Sum of the roots of unity statement

Further reading

  1. Web https://en.wikipedia.org/wiki/Root_of_unity, Summation
About this page
Tag02PETK9PQ4
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Kindstatement, proposition
WritingW0 stub
MSC11R18
StatusThis copy of the site has no build data. Run m2 status 02PETK9PQ4.
UsesPrimitive root of unity, Sum of a finite geometric progression

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