Math 2.0

Geometry Theorem

A tangent is perpendicular to the radius

Builds on Tangent line to a circleCircleVectors are perpendicular if and only if their dot product is zero

Statement

Let CC be a circle with the centre OO and the radius r>0r > 0 in the Euclidean plane ℝ2\mathbb{R}^2. Let TT be a point of CC, and let ℓ\ell be a line through TT. Then ℓ\ell is tangent to CC at TT if and only if ℓ\ell is perpendicular to the radius OTOT. That is, (X−T)⋅(T−O)=0(X - T) \cdot (T - O) = 0 for each point XX of ℓ\ell.

Remarks

A proof: for X=T+tvX = T + t v on ℓ\ell, we have ∥X−O∥2=r2+2t v⋅(T−O)+t2∥v∥2\|X - O\|^2 = r^2 + 2t\, v \cdot (T - O) + t^2 \|v\|^2. So t=0t = 0 is the only point of ℓ\ell on CC if and only if v⋅(T−O)=0v \cdot (T - O) = 0. Thus each point of CC has exactly one tangent line. The same holds for a sphere and its tangent plane in ℝ3\mathbb{R}^3.

Reading path

To understand this page from the ground up, read these 7 pages in order. The foundations come first.

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Each page uses the pages above it. The colour of the bar on a box shows how strong the evidence is, and the box also gives it as text. The list has the same pages.
  • no evidence level
  1. Angle between two vectors concept
  2. Circle concept
  3. Length of a vector concept
  4. Tangent line to a circle concept
  5. Geometric formula for the dot product statement
  6. Vectors are perpendicular if and only if their dot product is zero statement
  7. A tangent is perpendicular to the radius statement

Further reading

  1. Web https://en.wikipedia.org/wiki/Tangent_lines_to_circles, lead section
  2. Web https://en.wikipedia.org/wiki/Tangent_lines_to_circles, Tangent lines to one circle
About this page
Tag031JV5S54D
URIm2://031JV5S54D
Kindstatement, theorem
WritingW0 stub
MSC51M04
StatusThis copy of the site has no build data. Run m2 status 031JV5S54D.
UsesTangent line to a circle, Circle, Vectors are perpendicular if and only if their dot product is zero

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