Math 2.0

Number theory Divisibility and primes Theorem

Bertrand's postulate

Builds on Prime number

Statement

Let nn be a positive integer. Then there is a prime number pp such that n<p≤2nn < p \le 2 n.

Remarks

For example, for n=10n = 10 the primes 11,13,17,1911, 13, 17, 19 are in the range 10<p≤2010 < p \le 20. An equivalent form: if pkp_k is the kk-th prime, then pk+1<2pkp_{k+1} < 2 p_k for each k≥1k \ge 1. The prime number theorem gives a stronger result for large nn, but Bertrand's postulate holds for each n≥1n \ge 1.

History

Joseph Bertrand stated the result as a conjecture in 1845. Chebyshev proved it in 1852.

Reading path

To understand this page from the ground up, read these 3 pages in order. The foundations come first.

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Each page uses the pages above it. The colour of the bar on a box shows how strong the evidence is, and the box also gives it as text. The list has the same pages.
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  1. Divisibility definition
  2. Prime number definition
  3. Bertrand's postulate statement

Further reading

  1. Web https://en.wikipedia.org/wiki/Bertrand%27s_postulate, lead section
About this page
Tag0FJTGZA4GS
URIm2://0FJTGZA4GS
Aliasesbertrand-chebyshev-theorem, chebyshev-theorem
Kindstatement, theorem
WritingW1 stated
MSC11N05
StatusThis copy of the site has no build data. Run m2 status 0FJTGZA4GS.
UsesPrime number
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