Math 2.0

Number theory Analytic number theory Theorem

Divergence of the sum of the reciprocals of the primes

Builds on Prime number

Statement

The series ∑p1p\sum_{p} \frac{1}{p}, where pp runs over the prime numbers, diverges. That is, the partial sums ∑p≤x1p\sum_{p \le x} \frac{1}{p} are not bounded as x→∞x \to \infty.

Remarks

The result implies Euclid's theorem, since a finite sum is bounded. The partial sums grow like ln⁡ln⁡x\ln \ln x. More precisely, ∑p≤x1p−ln⁡ln⁡x\sum_{p \le x} \frac{1}{p} - \ln \ln x has a finite limit as x→∞x \to \infty. In contrast, the sum of 1/n21 / n^2 over all positive integers nn converges. So the primes are not as rare as the squares.

History

Euler proved the result in 1737. Erdős gave an elementary proof by upper and lower estimates.

Reading path

To understand this page from the ground up, read these 3 pages in order. The foundations come first.

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Each page uses the pages above it. The colour of the bar on a box shows how strong the evidence is, and the box also gives it as text. The list has the same pages.
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  1. Divisibility definition
  2. Prime number definition
  3. Divergence of the sum of the reciprocals of the primes statement

Further reading

  1. Web https://en.wikipedia.org/wiki/Divergence_of_the_sum_of_the_reciprocals_of_the_primes, lead section
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