Math 2.0

Real functions Definition

Cauchy principal value

Builds on Real numbers

Definition

Let a<b<ca < b < c be real numbers. Let ff be a function on [a,c]∖{b}[a, c] \setminus \{b\} that is integrable on [a,b−ε][a, b - \varepsilon] and on [b+ε,c][b + \varepsilon, c] for each ε\varepsilon with 0<ε<min⁡(b−a,c−b)0 < \varepsilon < \min(b - a, c - b). If the limit p.v.⁡∫acf(x) dx=lim⁡ε→0+(∫ab−εf(x) dx+∫b+εcf(x) dx)\operatorname{p.v.} \int_a^c f(x) \, dx = \lim_{\varepsilon \to 0^+} \left( \int_a^{b - \varepsilon} f(x) \, dx + \int_{b + \varepsilon}^{c} f(x) \, dx \right) exists, it is the Cauchy principal value of the integral of ff over [a,c][a, c]. Let ff be a function on ℝ\mathbb{R} that is integrable on each interval [−R,R][-R, R]. If the limit p.v.⁡∫−∞∞f(x) dx=lim⁡R→∞∫−RRf(x) dx\operatorname{p.v.} \int_{-\infty}^{\infty} f(x) \, dx = \lim_{R \to \infty} \int_{-R}^{R} f(x) \, dx exists, it is the Cauchy principal value of the integral of ff over ℝ\mathbb{R}.

Remarks

The integral ∫−11dxx\int_{-1}^{1} \frac{dx}{x} does not exist as an improper integral, but p.v.⁡∫−11dxx=0\operatorname{p.v.} \int_{-1}^{1} \frac{dx}{x} = 0, because the two parts cancel. Similarly, p.v.⁡∫−∞∞x dx=0\operatorname{p.v.} \int_{-\infty}^{\infty} x \, dx = 0, because ∫−RRx dx=0\int_{-R}^{R} x \, dx = 0 for each RR. When the improper integral exists, the principal value exists and has the same value. Principal values occur in the evaluation of real integrals by residues when the integrand has a pole on the real axis.

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Further reading

  1. Web https://en.wikipedia.org/wiki/Cauchy_principal_value, Formulation
  2. Web https://en.wikipedia.org/wiki/Cauchy_principal_value, Examples
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