Math 2.0

Harmonic analysis on Euclidean spaces Hardy spaces and BMO Theorem

Coifman–Rochberg–Weiss commutator theorem

Builds on Bounded mean oscillationSingular integral operatorRiesz transformLp spaceHilbert transform

Statement

Let n≥1n \ge 1 and 1<p<∞1 < p < \infty. For a locally integrable function bb on ℝn\R^n and an operator TT, let [b,T][b, T] be the commutator [b,T]f=b Tf−T(bf)[b, T] f = b \, Tf - T(bf), defined for smooth ff with compact support.

Let TT be a singular integral operator with kernel Ω(x/∣x∣)/∣x∣n\Omega(x/\abs{x})/\abs{x}^n. Here Ω\Omega is infinitely differentiable on the unit sphere and has mean zero. Let R1,…,RnR_1, \dots, R_n be the Riesz transforms, and write ∥⋅∥\norm{\cdot} for the operator norm on the Lp space Lp(ℝn)L^p(\R^n).

  1. If bb has bounded mean oscillation, then [b,T][b, T] extends to a bounded operator on Lp(ℝn)L^p(\R^n). Moreover ∥[b,T]∥≤C∥b∥BMO\norm{[b, T]} \le C \norm{b}_{\mathrm{BMO}}, where CC depends only on nn, pp and Ω\Omega.
  2. If [b,Rj][b, R_j] is bounded on Lp(ℝn)L^p(\R^n) for every j=1,…,nj = 1, \dots, n, then bb is in BMO. Moreover ∥b∥BMO≤C∑j=1n∥[b,Rj]∥\norm{b}_{\mathrm{BMO}} \le C \sum_{j=1}^n \norm{[b, R_j]}, where CC depends only on nn and pp.

Remarks

One proof of part 1 uses a conjugation trick. For complex zz, the operator Tzf=ezbT(e−zbf)T_z f = e^{zb} T(e^{-zb} f) satisfies ddzTz∣z=0=[b,T]\frac{d}{dz} T_z \big\vert_{z = 0} = [b, T]. By the John–Nirenberg inequality, ep Re(z)be^{p \, \mathrm{Re}(z) b} is a Muckenhoupt ApA_p weight when ∣z∣∥b∥BMO\abs{z} \norm{b}_{\mathrm{BMO}} is small. So, by weighted theory, TzT_z is bounded on LpL^p uniformly for small ∣z∣\abs{z}. The Cauchy integral formula for the derivative then gives the bound on [b,T][b, T].

For n=1n = 1 the only Riesz transform is the Hilbert transform HH, and the theorem says that [b,H][b, H] is bounded on Lp(ℝ)L^p(\R) exactly when b∈BMO(ℝ)b \in \mathrm{BMO}(\R). Example: b(x)=log⁡∣x∣b(x) = \log \abs{x} is unbounded, so the multiplication operator by bb is unbounded on LpL^p, yet [b,H][b, H] is bounded because b∈BMOb \in \mathrm{BMO}.

Going deeper

For a student

The theorem gives a new characterization of BMO through operators, complementing its definition by mean oscillations and Fefferman's duality with H1H^1. By duality it is equivalent to a factorization theorem for H1H^1: every f∈H1(ℝn)f \in H^1(\R^n) can be written as ∑k∑j(gk,jRjhk,j+hk,jRjgk,j)\sum_k \sum_j \left( g_{k,j} R_j h_{k,j} + h_{k,j} R_j g_{k,j} \right) with ∑k∑j∥gk,j∥p′∥hk,j∥p<∞\sum_k \sum_j \norm{g_{k,j}}_{p'} \norm{h_{k,j}}_p < \infty. Commutators with BMO functions appear in the study of div-curl lemmas in compensated compactness and of elliptic equations with VMO coefficients. The commutator [b,T][b, T] is compact on LpL^p exactly when bb is in the closure of smooth compactly supported functions in BMO, a result of Uchiyama.

Reading path

To understand this page from the ground up, read these 6 pages in order. The foundations come first.

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Each page uses the pages above it. The colour of the bar on a box shows how strong the evidence is, and the box also gives it as text. The list has the same pages.
  • no evidence level
  1. Bounded mean oscillation concept
  2. Hilbert transform concept
  3. Lp space concept
  4. Riesz transform concept
  5. Singular integral operator concept
  6. Coifman–Rochberg–Weiss commutator theorem statement

Further reading

  1. Web https://en.wikipedia.org/wiki/Bounded_mean_oscillation
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MSC42B20, 47B47, 42B35
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AboutBounded mean oscillation, Singular integral operator
UsesBounded mean oscillation, Singular integral operator, Riesz transform, Lp space, Hilbert transform

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