Math 2.0

Mathematical logic and foundations Proposition

Composition of surjections is surjective

Builds on Surjective functionFunction composition

Statement

Let f ⁣:A→Bf \colon A \to B and g ⁣:B→Cg \colon B \to C be surjective functions. Then the composition g∘f ⁣:A→Cg \circ f \colon A \to C is surjective.

Remarks

Proof: let c∈Cc \in C. Since gg is surjective, c=g(b)c = g(b) for some b∈Bb \in B. Since ff is surjective, b=f(a)b = f(a) for some a∈Aa \in A. Then c=(g∘f)(a)c = (g \circ f)(a). A partial converse holds: if g∘fg \circ f is surjective, then gg is surjective. The function ff need not be surjective. Together with the result for injections, this shows that a composition of bijections is a bijection.

Reading path

To understand this page from the ground up, read these 17 pages in order. The foundations come first.

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Each page uses the pages above it. The colour of the bar on a box shows how strong the evidence is, and the box also gives it as text. The list has the same pages.
  • no evidence level
  1. Element definition
  2. Proposition concept
  3. Set definition
  4. Implication definition
  5. Predicate definition
  6. Ordered pair definition
  7. Existential quantifier definition
  8. Universal quantifier definition
  9. Cartesian product definition
  10. Subset definition
  11. Uniqueness quantifier definition
  12. Binary relation definition
  13. Function definition
  14. Codomain definition
  15. Function composition definition
  16. Surjective function definition
  17. Composition of surjections is surjective statement

Further reading

  1. Web https://en.wikipedia.org/wiki/Surjective_function, Composition and decomposition
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Tag07EH4R3RVQ
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Aliasessurjective-comp
Kindstatement, proposition
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MSC03E20
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UsesSurjective function, Function composition

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