Math 2.0

Harmonic analysis on Euclidean spaces Convergence of Fourier series Theorem

Dirichlet conditions

Builds on Bounded variationFourier seriesDirichlet kernelJump discontinuityPeriodic function

Statement

Let f ⁣:ℝ→ℂf \colon \R \to \C be a periodic function of period 2π2\pi that has bounded variation on [−π,π][-\pi, \pi]. Let SNfS_N f be the partial sums of its Fourier series.

  1. For every x∈ℝx \in \R the one-sided limits f(x+)f(x^+) and f(x−)f(x^-) exist, and lim⁡N→∞SNf(x)=f(x+)+f(x−)2.\lim_{N \to \infty} S_N f(x) = \frac{f(x^+) + f(x^-)}{2}.
  2. If moreover ff is continuous on an open interval II, then SNf→fS_N f \to f uniformly on every closed bounded interval contained in II.

Remarks

A function of bounded variation is a difference of two monotone functions, so it suffices to treat a monotone ff. One writes SNf(x)−sS_N f(x) - s as an integral of f(x+t)+f(x−t)−2sf(x + t) + f(x - t) - 2s against the Dirichlet kernel over [0,π][0, \pi], with s=12(f(x+)+f(x−))s = \frac{1}{2}(f(x^+) + f(x^-)). The second mean value theorem for integrals, together with the uniform boundedness of ∫0asin⁡((N+1/2)t)t dt\int_0^a \frac{\sin((N + 1/2) t)}{t} \, dt in aa and NN, controls the part near t=0t = 0, and the Riemann–Lebesgue lemma handles the rest. Dirichlet's original conditions are that ff is bounded on a period, with finitely many maxima and minima and finitely many discontinuities there. Such an ff has bounded variation, so Jordan's form above contains them. Example: for the square wave, equal to sgn⁡x\operatorname{sgn} x on (−π,π)(-\pi, \pi), the series converges to 00 at the jumps, the average of −1-1 and 11, and to f(x)f(x) elsewhere. Bounded variation cannot be replaced by continuity: there are continuous functions whose Fourier series diverge at a point.

Going deeper

For a student

This is the convergence theorem used in most applications, since piecewise monotone and piecewise smooth functions have bounded variation. It is a pointwise test, like the Dini test; the two tests are independent, and neither implies the other. Part 2 explains why the convergence for the square wave is uniform away from the jumps but not near them, where the Gibbs phenomenon appears. Camille Jordan stated the test in this form, for functions of bounded variation.

Reading path

To understand this page from the ground up, read these 6 pages in order. The foundations come first.

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  1. Bounded variation concept
  2. Dirichlet kernel concept
  3. Fourier series concept
  4. Jump discontinuity concept
  5. Periodic function concept
  6. Dirichlet conditions statement

Where this leads

2 pages build on this one.

Further reading

  1. Web https://en.wikipedia.org/wiki/Dirichlet–Jordan_test
About this page
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Kindstatement, theorem
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AboutFourier series, Bounded variation
UsesBounded variation, Fourier series, Dirichlet kernel, Jump discontinuity, Periodic function

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