Math 2.0

Functions of a complex variable Singularities and residues Lemma

Estimation lemma

Builds on Contour integralCircle integral

Statement

Let γ:[a,b]→ℂ\gamma : [a, b] \to \mathbb{C} be a continuous and piecewise continuously differentiable path with length L(γ)=∫ab∣γ′(t)∣ dtL(\gamma) = \int_a^b |\gamma'(t)| \, dt. Let ff be a complex function that is continuous on the image of γ\gamma. Let M≥0M \ge 0 be a real number with ∣f(z)∣≤M|f(z)| \le M for each zz on the image of γ\gamma. Then the contour integral of ff along γ\gamma satisfies ∣∫γf(z) dz∣≤M L(γ).\left| \int_\gamma f(z) \, dz \right| \le M \, L(\gamma).

Remarks

For a circle integral over ∣z−c∣=R|z - c| = R, the bound is ∣∮f(z) dz∣≤2πRM\left| \oint f(z) \, dz \right| \le 2 \pi R M. Proof: ∣∫abg(t) dt∣≤∫ab∣g(t)∣ dt\left| \int_a^b g(t) \, dt \right| \le \int_a^b |g(t)| \, dt for a complex function gg, and ∣f(γ(t))γ′(t)∣≤M∣γ′(t)∣|f(\gamma(t)) \gamma'(t)| \le M |\gamma'(t)|. A typical use shows that the integral over a large half-circle goes to 00 as the radius goes to ∞\infty.

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  1. Complex numbers object
  2. Complex exponential definition
  3. Contour integral definition
  4. Circle integral definition
  5. Estimation lemma statement

Where this leads

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Further reading

  1. Web https://en.wikipedia.org/wiki/Estimation_lemma, lead section
About this page
Tag0DJMGPN8K9
URIm2://0DJMGPN8K9
Aliasesml-inequality, ml-lemma
Kindstatement, lemma
WritingW0 stub
MSC30A10
StatusThis copy of the site has no build data. Run m2 status 0DJMGPN8K9.
UsesContour integral, Circle integral
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