Linear and multilinear algebra; matrix theory Vector spaces Theorem
Every linearly independent set extends to a basis
Builds on BasisLinear independence
Statement
Let be a field, let be a vector space over , and let be a linearly independent set. Then there is a basis of with .
Remarks
For finite-dimensional , add to , one at a time, a vector that is not in the span of the current set. This stops after finitely many steps. In general, the proof uses Zorn's lemma. A stronger form: if , with independent and spanning, then a basis exists with . For example, extends to the basis of .
Reading path
To understand this page from the ground up, read these 8 pages in order. The foundations come first.
Show the path as a graph
- no evidence level
- Vector space definition
- Linear combination definition
- Linear subspace definition
- Linear independence definition
- Linear span definition
- Spanning set definition
- Basis definition
- Every linearly independent set extends to a basis statement
Further reading
About this page
| Tag | 0M4SXE5WW3 |
|---|---|
| URI | m2://0M4SXE5WW3 |
| Kind | statement, theorem |
| Writing | W0 stub |
| MSC | 15A03 |
| Status | This copy of the site has no build data. Run m2 status 0M4SXE5WW3. |
| Uses | Basis, Linear independence |
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