Math 2.0

Real functions Proposition

Exponentials dominate powers in sequences

Builds on Limit of a sequenceThe sequence r^n tends to infinity for r > 1

Statement

Let kk be a natural number and let rr be a real number with r>1r > 1. Then lim⁡n→∞nkrn=0.\lim_{n \to \infty} \frac{n^k}{r^n} = 0.

Remarks

For k=1k = 1 and r=2r = 2, it says n/2n→0n / 2^n \to 0. The terms are 1/2,2/4,3/8,4/16,…1/2, 2/4, 3/8, 4/16, \dots. One proof uses the ratio of consecutive terms. The ratio (n+1)knk⋅1r\frac{(n+1)^k}{n^k} \cdot \frac{1}{r} tends to 1/r<11/r < 1, so the terms eventually shrink by a fixed factor. In the language of little o notation, it says nk=o(rn)n^k = o(r^n). The node exponential growth beats polynomial growth gives the version for real variables.

Reading path

To understand this page from the ground up, read these 7 pages in order. The foundations come first.

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Each page uses the pages above it. The colour of the bar on a box shows how strong the evidence is, and the box also gives it as text. The list has the same pages.
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  1. Sequence definition
  2. Real sequence definition
  3. Geometric sequence definition
  4. Limit of a sequence definition
  5. Sequence tending to infinity definition
  6. The sequence r^n tends to infinity for r > 1 example
  7. Exponentials dominate powers in sequences statement

Further reading

  1. Web https://en.wikipedia.org/wiki/Big_O_notation, Exponentials dominate powers
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Kindstatement, proposition
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MSC26A12
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UsesLimit of a sequence, The sequence r^n tends to infinity for r > 1

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