Math 2.0

Geometry Theorem

Exterior angle theorem

Builds on TriangleAngle at a pointAngle sum of a triangle

Statement

Let ABCABC be a triangle in a Euclidean space ℝn\mathbb{R}^n, and let ∠\angle denote the angle at a point. Let DD be a point such that CC lies strictly between BB and DD on the line BCBC. Then the exterior angle at CC is the sum of the two interior angles at the other vertices: ∠ACD=∠BAC+∠CBA.\angle ACD = \angle BAC + \angle CBA.

Remarks

The angles ∠ACD\angle ACD and ∠ACB\angle ACB add up to π\pi. Thus the statement follows from the angle sum of a triangle. A consequence is that the exterior angle is greater than each of the two remote interior angles. This weaker form does not need the parallel postulate.

History

In Book I of Euclid's Elements, the weaker form is Proposition 16. The form with the sum is part of Proposition 32 of the same book. Many school books call the form with the sum the exterior angle theorem.

Reading path

To understand this page from the ground up, read these 4 pages in order. The foundations come first.

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Each page uses the pages above it. The colour of the bar on a box shows how strong the evidence is, and the box also gives it as text. The list has the same pages.
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  1. Angle at a point concept
  2. Triangle concept
  3. Angle sum of a triangle statement
  4. Exterior angle theorem statement

Where this leads

1 page builds on this one.

Further reading

  1. Web https://en.wikipedia.org/wiki/Exterior_angle_theorem, High school exterior angle theorem
About this page
Tag0NTSE7EREA
URIm2://0NTSE7EREA
Kindstatement, theorem
WritingW1 stated
MSC51M04
StatusThis copy of the site has no build data. Run m2 status 0NTSE7EREA.
UsesTriangle, Angle at a point, Angle sum of a triangle
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