Saccheri–Legendre theorem
Builds on Absolute geometryTriangleAngle at a pointExterior angle theorem
Statement
Let be an absolute plane that satisfies the axiom of Archimedes. Then the sum of the three angles of every triangle in is at most two right angles.
Remarks
The proof starts from a triangle and builds a new triangle with the same angle sum, one of whose angles is at most half of the angle at . Repeating this times gives a triangle with the same angle sum and an angle at most times the angle at . If the angle sum exceeded two right angles by some angle , the axiom of Archimedes would give a step where this small angle is less than . Then the other two angles would sum to more than two right angles, which contradicts the exterior angle theorem. The axiom of Archimedes is needed: Max Dehn built non-Archimedean geometries in which the other axioms hold and some triangles have angle sum greater than two right angles.
Going deeper
For a student
The theorem is one of the main results of absolute geometry. With it, the parallel postulate is equivalent to the existence of a single triangle with angle sum . The defect of a triangle is two right angles minus its angle sum. It is additive when a triangle is cut into two, and in the hyperbolic plane it is proportional to the area.
Reading path
To understand this page from the ground up, read these 6 pages in order. The foundations come first.
Show the path as a graph
- no evidence level
- Absolute geometry concept
- Angle at a point concept
- Triangle concept
- Angle sum of a triangle statement
- Exterior angle theorem statement
- Saccheri–Legendre theorem statement
Further reading
About this page
| Tag | 1Y2XK0QJDX |
|---|---|
| URI | m2://1Y2XK0QJDX |
| Kind | statement, theorem |
| Writing | W0 stub |
| MSC | 51F05, 51M09 |
| Status | This copy of the site has no build data. Run m2 status 1Y2XK0QJDX. |
| About | Absolute geometry |
| Uses | Absolute geometry, Triangle, Angle at a point, Exterior angle theorem |
| Same as |
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