Math 2.0

Partial differential equations Definition

Fokker–Planck equation

Builds on Stochastic differential equationWiener processProbability density functionPartial derivative

Definition

Let n,d≥1n, d \ge 1. Let μ ⁣:ℝn×[0,∞)→ℝn\mu \colon \R^n \times [0, \infty) \to \R^n and σ ⁣:ℝn×[0,∞)→ℝn×d\sigma \colon \R^n \times [0, \infty) \to \R^{n \times d} be smooth. Let D=12σσTD = \frac{1}{2}\sigma \sigma^T, a symmetric positive semidefinite n×nn \times n matrix at each point. The Fokker–Planck equation with drift μ\mu and diffusion matrix DD is the equation for p(x,t)p(x, t): ∂tp=−∑i=1n∂xi(μi p)+∑i,j=1n∂xi∂xj(Dij p),\partial_t p = -\sum_{i=1}^{n} \partial_{x_i}\big(\mu_i\, p\big) + \sum_{i,j=1}^{n} \partial_{x_i} \partial_{x_j}\big(D_{ij}\, p\big), where ∂\partial denotes partial derivatives. It is associated with the stochastic differential equation dXt=μ(Xt,t) dt+σ(Xt,t) dWtdX_t = \mu(X_t, t)\, dt + \sigma(X_t, t)\, dW_t, where WW is a dd-dimensional Wiener process.

Remarks

Under suitable regularity of μ\mu and σ\sigma, if XtX_t has a smooth probability density p(⋅,t)p(\cdot, t), then pp solves this equation. Example: for n=d=1n = d = 1, μ=0\mu = 0 and σ=1\sigma = 1, the equation is pt=12pxxp_t = \frac{1}{2} p_{xx}. Its solution p(x,t)=(2πt)−1/2e−x2/(2t)p(x, t) = (2\pi t)^{-1/2} e^{-x^2/(2t)} is the density of WtW_t; one checks pt=12pxxp_t = \frac{1}{2}p_{xx} by direct differentiation. Non-example: pt=−12pxxp_t = -\frac{1}{2} p_{xx} is not a Fokker–Planck equation, since it would need D=−12D = -\frac{1}{2}, which is not positive semidefinite. The equation is also called the forward Kolmogorov equation. In one dimension it reads pt=−(μp)x+(Dp)xxp_t = -(\mu p)_x + (D p)_{xx}.

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  1. Euclidean space object
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  8. Fokker–Planck equation definition

Further reading

  1. Web https://en.wikipedia.org/wiki/Fokker%E2%80%93Planck_equation
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MSC35Q84, 60J60
DefinesFokker–Planck equation
UsesStochastic differential equation, Wiener process, Probability density function, Partial derivative

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